You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Answer:
x = 0
y = -4
negative 4 cuz the line goes down, meaning it's negative
Answer:
Step-by-step explanation:
wefasv
Answer:
x = -4
y = -12
Step-by-step explanation:
Since y is 3x,
3x = 2x - 4
On solving we get x as -4
Substitute x and we get y as -12
Alternatively, you could have wrote down the formula instead of describing it with words. maybe then I could have helped you
