Question

A triangle has two sides of lengths 6 and 9. What value coul the length of the third side be?

Answer 1

Answer:

(a) -2,0 and 2,5 and (b) 2,-1 and 10,9

The question is incomplete without the answer choice. Let's consider the following:

A line has a slope of -4/5. Which ordered pairs could be points on a line that is perpendicular to this line? select two options

a) -2,0 and 2,5

b) -4,5 and 4,-5

c) -3,4 and 2,0

d) 1,-1 and 6,-5

e) 2,-1 and 10,9

Answer 2

Answer:

The length of any side of a triangle cannot exceed the sum of the lengths of the other two sides. (I am allowing three collinear points to be considered vertices of a degenerate triangle.) Therefore, if two sides have length 6 cm and 9 cm, the third side has length between 9–6 = 3 cm and 9+6 = 15 cm. On the other hand, if we take a line segment whose length is any real number between 3 and 15 cm and construct a circle of radius 6 cm with center at one end and another circle of radius 15 cm with center at the other end, the two circles will intersect and a point of intersection will be the third vertex of a triangle with base the given line segment and whose two other sides are of length 6 cm and 9 cm. So the third side can be of any length between 3 and 15 cm.

Step-by-step explanation: