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Vladimir [108]
2 years ago
10

A triangle has two sides of lengths 6 and 9. What value coul the length of the third side be?

Mathematics
2 answers:
topjm [15]2 years ago
8 0

Answer:

(a) -2,0 and 2,5 and (b) 2,-1 and 10,9

The question is incomplete without the answer choice. Let's consider the following:

A line has a slope of -4/5. Which ordered pairs could be points on a line that is perpendicular to this line? select two options

a) -2,0 and 2,5

b) -4,5 and 4,-5

c) -3,4 and 2,0

d) 1,-1 and 6,-5

e) 2,-1 and 10,9

Sveta_85 [38]2 years ago
5 0

Answer:

The length of any side of a triangle cannot exceed the sum of the lengths of the other two sides. (I am allowing three collinear points to be considered vertices of a degenerate triangle.) Therefore, if two sides have length 6 cm and 9 cm, the third side has length between 9–6 = 3 cm and 9+6 = 15 cm. On the other hand, if we take a line segment whose length is any real number between 3 and 15 cm and construct a circle of radius 6 cm with center at one end and another circle of radius 15 cm with center at the other end, the two circles will intersect and a point of intersection will be the third vertex of a triangle with base the given line segment and whose two other sides are of length 6 cm and 9 cm. So the third side can be of any length between 3 and 15 cm.

Step-by-step explanation:

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Which correlation does the two-way table suggest?
natima [27]

Answer:

The answer is C.

Hope this helps :)

<em>-ilovejiminssi♡</em>

6 0
2 years ago
In an anthropology class there are 77 anthropology majors and 1414 non-anthropology majors. 55 students are randomly selected to
Nata [24]

Answer:

P = 0.9989

Step-by-step explanation:

In order to do this, I will use the following numbers to make the calculations easier. In this case, We'll say that we have 7 majors and 14 non majors anthopology to present a topic.

This means that in the class we have 21 students.

Now, we choose 5 of them, and we want to know the probability that 1 of them is non major.

First, we need to calculate the number of ways we can select the students in all cases, and then, the probability.

First, we'll use the combination formula, to calculate the number of ways we can select the 5 students out of the 21. We use combination, because it does not matter the order that the students are selected.

C = m! / n!(m - n)!

Where:

m: number of students

n: number of selected students out of m.

With this expression we will calculate first, how many ways we can choose the 5 students out of 21:

C1 = 21! / 5!(21-5)! = 20,349

Now let's calculate the number of ways you can get the all 5 students are non majors:

C2 = 14! / 5!(14 - 5)! = 2002

Now we need to know the number of ways we can get 4 non majors and 1 major:

C3 = C3' * C3''

C3' represents the number of ways we can get 4 non majors and the C3'' represents the number of ways we can get 1 major.

C3' = 14! / 4!(14 - 4)! = 1,001

C3'' = 7! / 1!(7 - 1)! = 7

C3 = 1001 * 7 = 7,007 ways to get 4 non majors and 1 major

Now the way to get 3 non majors and 2 majors, we do the same thing we do to get 4 non majors and 1 major, but changing the numbers. Then the way to get 2 non majors and 3 majors, and finally 1 non major and 4 majors:

3 non majors and 2 majors:

C4 = C4' * C4'' = [14! / 3!(14 - 3)!] * [7! / 2!(7 - 2)!] = 7,644

2 non majors and 3 majors:

C5 = C5' * C5'' = [14! / 2!(14 - 2)!] * [7! / 3!(7 - 3)!] = 3,185

1 non major and 4 majors:

C6 = C6' * C6'' = [14! / 1!(14 - 1)!] * [7! / 4!(7 - 4)!] = 490

Finally to know the probability of getting 1 out of the 5 to be non major, we have to sum all the previous results, and divide them by the ways we can choose the 5 students (C1):

P = 2,002 + 7,007 + 7,644 + 3,185 + 490 / 20,349

P = 0.9989

5 0
3 years ago
Write 1. 995x10^-22 in standard form.
densk [106]
That would be 177.5 in standard form.
5 0
3 years ago
Point A is at (-2,-2)?<br> true or false
vladimir1956 [14]

A= (2,-2)
B= (-2,-2)
C=(2,4)
D=(-2,2)

if this helped Brainliest me on this answer it helps alot :))

6 0
1 year ago
Which of these angles can replace x in tan (x)?
Alex17521 [72]

Answer:

C. φ

Step-by-step explanation:

tan \phi \:  =  \frac{6}{5}  \\  \\ tan x \:  =  \frac{6}{5}  \\  \implies \: x =  \phi

Thus \Phi can replace x

6 0
2 years ago
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