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3 years ago

HEY I NEED HELP FAST

SAT

2 answers:

iragen [17]3 years ago

7 0

The answer is A

hope this helps

balu736 [363]3 years ago

3 0

I agree the answers is going to be (A)

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Simplify: 1 + i + i^2 + i^3 +i^4 +i^5 if i^2 =-1.

Vika [28.1K]

1 + i + i ² + i ³ + i ⁴ + i ⁵ = 1 + i + i ² (1 + i + i ² + i ³)

… = 1 + i + i ² (1 + i + i ² (1 + i ))

… = 1 + i + (-1) (1 + i + (-1) (1 + i ))

… = 1 + i + (-1) (1 + i - 1 - i )

… = 1 + i

Alternatively, notice that

1 - i ⁶ = (1 - i ) (1 + i + i ² + i ³ + i ⁴ + i ⁵)

so that

1 + i + i ² + i ³ + i ⁴ + i ⁵ = (1 - i ⁶) / (1 - i )

Now, i ⁶ = (i ²)³ = (-1)³ = -1, so

1 + i + i ² + i ³ + i ⁴ + i ⁵ = (1 - (-1)) / (1 - i )

… = 2 / (1 - i )

Multiply the numerator and denominator by the conjugate of 1 - i :

… = 2 (1 + i ) / ((1 - i ) (1 + i ))

… = 2 (1 + i ) / (1² - i ²)

… = 2 (1 + i ) / (1 + 1)

… = 1 + i

3 0

3 years ago

Read 2 more answers

The surface tension of water in air is approximately 0.00518 lbf/ft. if the atmospheric pressure is 14.7psia, what is the pressu

strojnjashka [21]

Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.

Given the following data:

Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.

Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.

Diameter = 0.01 mm to m = 0.00001 m.

Radius, r = $\frac{diamter}{2} =\frac{0.0001}{2}$ = 0.000005 m.

<h3>How to determine the pressure inside a droplet.</h3>

For a droplet with only one surface, its pressure is given by this formula:

$P_1-P_2=\frac{2 \tau}{r} \\\\P_1=\frac{2 \tau}{r}+P_2$

Substituting the given parameters into the formula, we have;

$P_1=\frac{2 \times 0.00702}{0.000005} + 101.35\\\\P_1=2808+ 101.35$

Inside pressure = 2,909.35 kPa.

Read more on pressure here: brainly.com/question/24827501

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2 years ago

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Answer:

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3 years ago

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Many friends does each have?

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Answer:

7 large stuffed animals and 20 small ones

Explanation:

Solve the system of equations

13S + 12L = 350

S + L = 27

L = 7

S = 20

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Answer:d

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