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3 years ago

10

If sinø=3/5 then tanø=?

1 answer:

nikdorinn [45]3 years ago

6 0

Answer:

p/h=3/5.

...b=4

cos theta = 4/5

tan theta = 3/4

Step-by-step explanation:

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Write each ratio as a fraction in the lowest terms

stich3 [128]

Answer:

1/4

Step-by-step explanation:

$(4\times \frac{3}{8} ) : (12\times \frac{1}{2} )\\\\\frac{4\times \frac{3}{8}}{12\times \frac{1}{2}}\\\\\mathrm{Multiply\:}12\times \frac{1}{2}\::\quad 6\\=\frac{4\times \frac{3}{8}}{6}\\\\\mathrm{Multiply\:}4\times \frac{3}{8}\::\quad \frac{3}{2}\\=\frac{\frac{3}{2}}{6}\\\\=\frac{3}{2\times \:6}\\\\=\frac{3}{12}\\\\=\frac{1}{4}$

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4 years ago

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What is the difference between the areas of a circular table with diameter 6ft and a circular table with diameter 8 ft ? Round y

miskamm [114]

Answer:

22 ft^2

Step-by-step explanation:

The area of a table with diameter 6 ft

A = pi r^2 = pi (6/2) ^2 = pi 3^2 = 9pi

The area of a table with diameter 8 ft

A = pi r^2 = pi (8/2) ^2 = pi 4^2 = 16pi

Subtract 16pi-9pi = 7pi

Using 3.14 for pi

7 * 3.14

21.98 ft^2

To the nearest square foot

22 ft^2

4 0

4 years ago

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HELP!!! I'm struggling in this class could you please help a person out?

mel-nik [20]

Answer:

Options (2) and (3)

Step-by-step explanation:

Rigid transformation like translation, rotation or reflection form the image with no change in the area or shape.

By applying dilation, area of the image shape gets dilated by the scale factor 'k'.

If k > 1, area of the image will be greater than the original shape.

If 0 < k < 1, are of the image will be smaller than the original.

Option (1),

There is a dilation by a scale factor of $\frac{2}{3}$ and $0$ ,

Therefore, image will be smaller than the original.

Option (2)

There are two dilations.

First dilation is by a scale factor of 2 and the second is by a scale factor of $\frac{2}{3}$ .

By first dilation area of the image will get doubled.

Followed by the dilation by a scale factor of $\frac{2}{3}$ , area of the image will be dilated by the scale factor = $2\times \frac{2}{3}$

= $\frac{4}{3}$

Since, $\frac{4}{3}>1$ , image will be greater than the original.

Option (3)

In this option polygon is dilated by a scale factor $\frac{3}{2}$ .

Since, $\frac{3}{2}>1$

Image will have the greater area than the original.

Option (4)

In this option polygon is dilated by a scale factor $\frac{1}{2}$ .

Therefore, area of the image will be less than the area of the original.

Options (2) and (3) will be the correct options.

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3 years ago

1/2 + 3/4 + 3/8 change your improper fraction into a mixed number.

Mademuasel [1]

Answer:

13/8

Step-by-step explanation:

5 0

3 years ago

A triangle with vertices at A(0,0),B(0,4),and C(6,0) is dilated to yield a triangle with vertices at A'(0,0),B'(0,10), and C'(15

kakasveta [241]

You can use 4/10 or 6/15

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3 years ago

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