9514 1404 393
Answer:
25
Step-by-step explanation:
Inverse variation means ...
y = k/x
For the given values, we can find k to be ...
k = xy = (5)(10) = 50
Then for x=2, we have ...
y = 50/x
y = 50/2
y = 25 . . . when x=2
325 meters if using full height of 324 meters for tower
277 meters if using observation platform height of 276 meters.
When the depression is 37 degrees, you can create a right triangle with the angles 90, 37, and 53 degrees. The distance from a point directly underneath the observer will be:
h/tan(37)
where
h = height of the observer.
And when the depression is 72 degrees, the distance will be:
h/tan(72)
So the distance between the two points will be the absolute value of:
h/tan(72) - h/tan(37)
=(tan(37)h)/tan(37)tan(72) - tan(72)h/(tan(37)tan(72))
=(tan(37)h - tan(72)h) /(tan(37)tan(72))
=h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
=h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
=h(-2.324129487/2.319200894)
=h*-1.002125125
And since we're looking for absolute value
=h*1.002125125
As for the value of "h" to use, that's unspecified in the problem. If you take h
to be the height of the Eiffel Tower, then it's 324 meters. If you take h to be
the highest observation platform on the Eiffel Tower, then it's 276 meters. In
any case, simply multiply h by the value calculated above:
=h*1.002125125
=324*1.002125125
= 324.6885406 m
=h*1.002125125
=276*1.002125125
=276.5865346
Answer:
W = kq1q2 / r
Step-by-step explanation:
W varies jointly as the product of q1 and q2 and inversely as radius r
Product of q1 and q2 = q1q2
W = (k*q1"q2) / r
W = kq1q2 / r
Where,
W = work
q1 = particle 1
q2 = particle 2
r = radius
k = constant of proportionality
The answer is W = kq1q2 / r
Answer:
<h3>#5</h3>
<u>Given vertices:</u>
These have same x-coordinate, so when connected form a vertical segment.
<u>The length of the segment is:</u>
The area of the rectangle is 72 square units, so the horizontal segment has the length of:
<u>Possible location of the remaining vertices (to the left from the given):</u>
and
<h3>#6</h3>
<u>Similarly to previous exercise:</u>
- (5, -8) and (5, 4) given with the area of 48 square units
<u>The distance between the given vertices:</u>
<u>The other side length is:</u>
<u>Possible location of the other vertices (to the right from the given):</u>
and
3+2=5
5/8. Hope that helps!
