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Natasha_Volkova [10]
3 years ago
15

What is the slope of the line given by the equation below? y + 2 = -3(x - 5)​

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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MechNerd has 3 dollars. He loses 1 dollar because he is dumb. How much does he have left?
Gnesinka [82]

Answer:

2 Dollars.

Step-by-step explanation:

He had 2 dollars left because he start with 3 and loses 1 which is subtraction (3-1) you are left with the answer 2 Dollars.

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18

Step-by-step explanation:

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URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x)​ , where neither polynomial is a constant
Nutka1998 [239]

Answer:

Always

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$ \implies P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$ \frac{P(x)}{Q(x)} $ = $ \frac{5x^2}{x} $ = 5x, a polynomial.

So, $ \frac{P(x)}{Q(x)} $ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $ \frac{1}{Q(x)} $ is never a polynomial.

Hence, the answer.

7 0
3 years ago
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