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Gelneren [198K]
3 years ago
11

Please help I will appreciate it

Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Answer:

For part A the value of m is 2/5

Step-by-step explanation:

When a system equation has no solution it means a equation is parallel and it doesn't intersect. And when a line is parallel to one another it has the same slope.

marin [14]3 years ago
8 0

Answer:

m = 2/5

Step-by-step explanation:

becuz to have no solutions, the lines would be parallel; and parallel lines have equal gradients.

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Help me what is the answer ?
pentagon [3]

Answer:

Correct choce is (a). 30.

Step-by-step explanation:

Given equation is f(x)=x^2-x.

Now we need to find the value of (fof)(3). Then select correct matching choice from the given choices. Where given choices are:

(a). 30

(a). 33

(a). 6

(a). -6

Now let's find  (fof)(3)

(fof)(3)=f(f(3))

(fof)(3)=f(3^2-3)

(fof)(3)=f(9-3)

(fof)(3)=f(6)

(fof)(3)=6^2-6

(fof)(3)=36-6

(fof)(3)=30

Hence correct choce is (a). 30.

7 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the given line. Include your work in your final answer.
Degger [83]

Answer:

y=1x+-1

Step-by-step explanation:

y=mx+b

m=slope which is 1/1 because it is rise over run (rising 1, running 1)

b=y-intercept form which is -1 because that is where the line meets the y axis

8 0
3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
Pleaseeeeee help <br><br> The measure of angle is (5pi)/6 The equivalent measurement in degrees is
Archy [21]

Answer:

To convert from degree to radian we multiply the angle by

π/180

To convert from radian to degree we multiply the angle by

180/π

5π/6,

Multiply by

180/π

=

5π/6 × 180/π = 5 × 30 = 150 degrees.

⇒5π/6 radian =150 degree.

7 0
3 years ago
How to solve please help thank you
Rashid [163]

her new balance is $105.

hope this helps.

7 0
3 years ago
Read 2 more answers
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