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yaroslaw [1]
3 years ago
12

. Find the current assets of a clothing store that has $62,300.00 in cash, $1,200.00 in accounts receivable, and $26,548.00 in m

erchandise.
$63,500.00
$90,048.00
$27,748.00
$88, 848.00
Mathematics
1 answer:
Alex3 years ago
5 0

Current assets is the sum of cash in hand, accounts receivable, and merchandise.

So we need to find the sum of all the figures given in the question.

Current assets = Cash in hand + Accounts receivable + Merchandise

Current assets = $62,300 + $1200 + $26,548 = $90,048

So $90,048 is the final answer.

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A farmer has two pieces of land in a parallelogram shape on the same base. He grows vegetables and flowers in two triangular pie
Hitman42 [59]

Step-by-step explanation:

In trapezoid ABCF, AB || CF.

Therefore, parallelograms ABEF & ABCD have same height and lie on the same base AB.

\therefore  Ar(\parallel^{gm} ABEF) = Ar(\parallel^{gm}ABCD)\\... (1)\\\\   \because\: Ar(\parallel^{gm} ABEF) \\=Ar(\triangle AFD) + Ar(\square \: ABED)....(2)  \\\\\&\: Ar(\parallel^{gm}ABCD)\\= Ar(\triangle BCE) +Ar(\square ABED)....(3)

From equations (1), (2) & (3), we find:

Ar(\triangle AFD) + Ar(\square \: ABED)  \\ = Ar(\triangle BCE) +Ar(\square ABED)  \\  \\ \purple {\boxed {\therefore  Ar(\triangle AFD)    = Ar(\triangle BCE)}}  \\

Thus, the two triangular pieces of land are equal in area.

Hence proved.

8 0
3 years ago
Geometry Helps please<br> (Only correct Answers only please) Thanks!
nlexa [21]

Answer:

301.44 cubic units

Step-by-step explanation:

volume \: of \: cone \\ \\   =  \frac{1}{3}\pi {r}^{2}  h \\  \\  =  \frac{1}{3}  \times 3.14 \times  {(6)}^{2}  \times 8 \\  \\  = \frac{1}{3}  \times 3.14 \times 36 \times 8  \\  \\  = 3.14 \times 12 \times 8 \\   \\ = 301.44 \:  {units}^{3}  \\  \\  \red{ \bold{volume \: of \: cone = 301.44 \:  {units}^{3}}}

7 0
3 years ago
Suppose that 600 yards of fencing material are available to fence in
postnew [5]

Answer:

Length = 150 yards

Width = 100 yards

Step-by-step explanation:

We want 600 yards of fencing that will result in the largest 2 fenced corrals, sharing a common border.

It will take the shape of a rectangle, with a dividing fence down the center.

Let W and L,  Width and Length of the larger enclosure.

See attachment.

W= Area of the larger enclosure.

The perimeter is 2W + 2L.

The dividing fence is 1W

We know that we only have 600 yards of fence, so:

2W + 2L + 1W = 600 yards

Area = W x L

---

3W + 2L  = 600    (yards)

2L  = 600 -3W

L = (600-3W)/2

L = 300 -(3/2)W

---

Use this expression in the Area calculation:

Area = W x L

Area = W x (300 -(3/2)W)

Area = 300W -(3/2)W^2)

To find the maximum area, take the first derivative and set to zero to find the value of W that results in the greatest area.

Area' = 300 -2(3/2)W)

0 = 300 - 3W

3W = 300

W = 100 yards

Since 3W + 2L  = 600

L = (600 - 3W)/2

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L = 150 yards

Area = 150*100 = 15,000 yards^2

 

8 0
3 years ago
Answerasap a1324242352352112
makkiz [27]

Answer:

For the first 1, the box plot is more helpful to find the  minimum distance. For the second one, the histogram is the best one to find 23 vehicles.

Step-by-step explanation:

Box plots are created based on medium, range, and mode. Histogram can show the exact numbers.

5 0
3 years ago
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Advocard [28]

Answer:

2/13

Step-by-step explanation:

There are thirteen shapes and out of that two are

3 0
3 years ago
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