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timama [110]
3 years ago
12

What's the definition of a imagine in math

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:A pic with numbers i dont know.Or maybe you were talking about imaginemath

Step-by-step explanation:

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How to do linear equations 27, 28,28,30
Mekhanik [1.2K]
#27.  
First cross multiply
2 (2a-3) = 3 (a-1)
next use the distribute property on both sides
4a - 6 = 3a - 3
combine like terms, subtract 3a from both sides and add 6 to both sides
a = 3

#28
cross multiply
3x = 4, then divide both sides by 3
x = 4/3

#30
add 1/4 to both sides
3/x = 1/2 + 1/4, find a common denominator for the right side fractions
3/x = 2/4 + 1/4 = 3/4
therefore, x = 4
6 0
3 years ago
Gilda drove 650miles at an average speed of 50 miles per hour.how many miles per hour faster would she have had to drive in orde
zzz [600]
T=650mi(hr/50mi)=13 hr

t-1=12 hr

12=650/(50+v)  multiply both sides by 50+v

600+12v=650  subtract 600 from both sides

12v=50  divide both sides by 12

v=25/6 mph

v≈4.17mph


6 0
3 years ago
Amanda's book bag is 0.10. Some of Amanda's pens are removed and replaced with pink pens. Her book bag still contains a total of
Marta_Voda [28]

Answer:

The number of pink pens can be 19 .

Step-by-step explanation:

Total Number of pens = 20

Let x be the number of pink pens

We are supposed to find If the probability of choosing a pink pen is close to 1, how many pink pens would you expect to see in Amanda's bag

Probability of choosing a pink pen = \frac{\text{Number of pink pens}}{\text{Total Number of pens}}

Probability of choosing a pink pen =\frac{x}{20}

ATQ

\frac{x}{20}≈1

x≈20

So, the number of pink pens can be 19 .

6 0
3 years ago
What is the constant variation in the equation 3y=6x? Explain. PLEASE HELP IM DESPERATE
lbvjy [14]
Hi Desperate!

anyways the equation for constant variation is y=kx
3y=6x is it, but we don't want the 3.
so we divide on both sides to cancel out the 3.
y=2x
4 0
3 years ago
F(x)=x^2 what is g(x)
AysviL [449]
Is C g(x) = -X^2 -3

This is the answer
4 0
3 years ago
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