Ask question

Ask question

All categories

3 years ago

12

A newborn boa constrictor measures 18 inches long and adult boa constrictor measures 9 times the length of the newborn + 2 inche

s how long is the adult

1 answer:

serg [7]3 years ago

4 0

Do 18x9 which is 162 plus 2 is 164.

You might be interested in

Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?

garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is $z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$ .

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be $z (x) = \cos x$ the base formula, where $x$ is measured in sexagesimal degrees. This expression must be transformed by using the following data:

$T = 180^{\circ}$ (Period)

$z_{min} = -4$ (Minimum)

$z_{max} = 5$ (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of $2\pi$ radians. In addition, the following considerations must be taken into account for transformations:

1) $x$ must be replaced by $\frac{2\pi\cdot x}{180^{\circ}}$ . (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

$\Delta z = \frac{z_{max}-z_{min}}{2}$

$\Delta z = \frac{5+4}{2}$

$\Delta z = \frac{9}{2}$

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

$z_{m} = \frac{z_{min}+z_{max}}{2}$

$z_{m} = \frac{1}{2}$

The new function is:

$z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)$

Given that $z_{m} = \frac{1}{2}$ , $\Delta z = \frac{9}{2}$ and $T = 180^{\circ}$ , the outcome is:

$z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0

3 years ago

The hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

konstantin123 [22]

Answer:

33 copies were paperback and 12 were hardcover.

Step-by-step explanation:

Let h represent the number of hardcover copies and p represent the number of paperback copies.

We know that the total number of copies was 45; this gives us the equation

h+p = 45

We know that each hardcover copy is 7 ounces; this gives us the expression 7h.

We also know that each paperback copy is 5 ounces; this gives us the expression 5p.

We know that the total weight was 249 ounces; this gives us the equation

7h+5p = 249

Together we have the system

$\left \{ {{h+p=45} \atop {7h+5p=249}} \right.$

We will use elimination to solve this. First we will make the coefficients of the variable p the same; to do this, we will multiply the top equation by 5:

$\left \{ {{5(h+p=45)} \atop {7h+5p=249}} \right. \\\\\left \{ {{5h+5p=225} \atop {7h+5p=249}} \right.$

To eliminate p, we will subtract the equations:

$\left \{ {{5h+5p=225} \atop {-(7h+5p=249)}} \right. \\\\-2h=-24$

Divide both sides by -2:

-2h/-2 = -24/-2

h = 12

There were 12 hardcover copies sold.

Substitute this into our first equation:

12+p=45

Subtract 12 from each side:

12+p-12 = 45-12

p = 33

There were 33 paperback copies sold.

3 0

3 years ago

Read 2 more answers

Help please asap just the answers

Stella [2.4K]

$\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

$\huge\underline{\sf{\red{Problem:}}}$

7.) Detemine the value of $\sf{ {3a}^{2} -b.}$

$\huge\underline{\sf{\red{Given:}}}$

$\quad\quad\quad\quad\sf{a = 2}$

$\quad\quad\quad\quad\sf{b = - 1}$

$\quad\quad\quad\quad\sf{c = - 3}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}$

$\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}$

$\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12 + 1 }$

$\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}$

8.) Find the value of $\sf{ {a}^{3} {b}^{3} - abc.}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}$

$\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}$

$\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}$

$\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

#CarryOnLearning

$\sf{\red{✍︎ C.Rose❀}}$

4 0

2 years ago

One side of a tabletop is 12x – 5 units long. Another side of the tabletop is 7x + 4 units long. If the tabletop is a square, wh

Trava [24]

Answer:

no c

Step-by-step explanation:

7 0

2 years ago

Looking for gf pls needed

Allisa [31]

I’m right here……………….

4 0

2 years ago