If f(x)= 3x+2 and g(x)= 4x, then
f(x)+g(x) = 3x+2+4x
= 7x+2
For f(g(x)), you work from the inside and work your way out. Another way of thinking is to go from right to left. (Inside/out and right/left are the same simply using different wording).
So what is g(x)? 4x.
Now, you take 4x and plug it into the f(x).
** Math--> English translation:
Look at the f(x) equation. Wherever you see an x in the f(x), replace the x with 4x [because 4x is the g(x)]. Basically, plug the g(x) into f(x).
So:
f(g(x)) becomes
f(4x) becomes
3 (4x)+2 = 12x+2
** Disclaimer: Notation may be inaccurate.
That's your answer. (Usually you leave it as so, but if your instructor wants it factored, then proceed).
As for the third part, I am unsure of a clear answer, so I am unable to provide an answer at the time.
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Hope that helped.
DISCLAIMER:
Always double check with a reliable source, as mistakes are a possibility. Never use this, or any, platform to cheat.
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Apply the Keep Flip Change rule here
1/4 has been kept the same
The sign has been changed
The other fraction needs to be flipped
Thus, z = -2/7
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
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Answer:
4 4/5
Step-by-step explanation:
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)
The correct answer is A because the line goes down left and up right.....choice B is a horizontal line which means it has a zero slope......choice C is a negative slope because it goes down right and up left.
