Answer:
x = 0 and y = 3
Step-by-step explanation:
Using elimination method, we can solve for x and y in the simultaneous equation
y = 2x + 3 .................................eqn 1
y = -3x + 3 .................................eqn 2
multiply equation 1 by 3 and equation 2 by 2, then we will have
(y = 2x + 3) × 3
(y = -3x + 3) × 2
3y = 6x + 9 ...............................eqn 3
2y = -6x + 6 ................................eqn 4
Add eqn 3 and 4 together and we will eliminate x and have
5y = 15
Divide both sides by 5, and we will have
y = 3
To solve for x, substitute 3 for y in eqn 1
y = 2x + 3
3 = 2x + 3
collect like terms
3 - 3 = 2x
0 = 2x
Therefore x = 0
Answer:
-72a^3 +108a^2
Step-by-step explanation:
(2a)(6a)(2a-8a+9)= (2a)(6a)(-6a+9)=12a^2(-6a+9)
= -72a^3 +108a^2
Given a number n, the addititive inverse is -n since n+(-n)=0. However
n+(-n) is the same as n-n which is 0 also.
SO adding the additive inverse it the same as subtracting
Answer:
28
Step-by-step explanation:
Add them and then divide by the number of numbers given
