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sineoko [7]
3 years ago
5

The equation y = 1.9 x can be used to determine the total weight in pounds, y, of the number of paperback books in the first pri

nting of Zamir’s novel, x. The equation was used to fill in the table below.
Weight of Books
Number of Books
Total Weight (in pounds)
100
190
150

200
380
250
475

What value is missing from the table?

lbs.
Mathematics
2 answers:
kari74 [83]3 years ago
8 0
I think it’s 180!!!!!!!!!!
andrew11 [14]3 years ago
4 0

Answer: The correct anwsr is 180

Step-by-step explanation:

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The truck is Karen tomato juice pineapple juice and grape juice bottles in a ratio of 2: 3: 2grape juice bottles and how many ju
tigry1 [53]

Answer:

7

Step-by-step explanation:

If the ratio is 2:3:2 that means that there is 2Karen tomato juice bottles, 3pineapple juice bottles and 2 grape juice bottles you just have to find the sum and get 7juice bottles

3 0
3 years ago
An animal shelter houses dogs, cats, and rabbits. there are 126 animals at the shelter. of the animals, 1/3 are cats. three four
viva [34]
Given that an animal shelter houses three kinds of animals: dogs, cats and rabbits and it has a total of 126 animals. 1/3 of the animals are cats. This means, 1/3 of 126 is 42. So there are 42 cats. 3/4 of the remaining animals, which is 84 are dogs. So 3/4 of 84 is 63. So there are 63 dogs. 63 dogs plus 42 cats is 105 animals. 126 minus 105 is 21. Therefore, there are only 21 rabbits. Hope this helps.
6 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
Given a polyhedron with 12 faces and 30 edges, how many vertices does it have?
larisa86 [58]

Answer:

It should have 20 vertices, and the name is dodecahedron

8 0
3 years ago
Need Help Rn!!!
fgiga [73]
It would be 5850 hope you get it right:)
7 0
3 years ago
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