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3 years ago

Find the midrange.

Mathematics

1 answer:

nirvana33 [79]3 years ago

5 0

Answer:

I believe it's 1.14

Step-by-step explanation:

Formula - M = (max + min) / 2

where:

M = midrange

max = maximum value in a data set

min = minimum value in a data set

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FromTheMoon [43]

The answer is d= 1/4
hope this helps

5 0

3 years ago

What’s is the answer to these two problems?

Len [333]

Answer:

Step-by-step explanation:

8 0

3 years ago

Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)

muminat

Answer:

The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = $\frac{-5}{2}$ x + $\frac{12}{2}$

Or, y = $\frac{-5}{2}$ x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = $\frac{-5}{2}$

Again,

The other line if passing through the points (- 2 , 3 ) And is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So, M = m = $\frac{-5}{2}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = $\frac{-5}{2}$ × ( - 2 ) + c

or, 3 = $\frac{10}{2}$ + c

Or, 3 = 5 + c

∴ c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope $\frac{-5}{2}$ and passing through points ( -2 , 3)

y = $\frac{-5}{2}$ x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And is perpendicular to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So, M' × m = - 1

Or, M' × $\frac{-5}{2}$ = - 1

Or, M' = $\frac{-1}{\frac{-5}{2}}$

Or, M' = $\frac{2}{5}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = $\frac{2}{5}$ × ( - 2 ) + c'

or, 3 = $\frac{- 4}{5}$ + c'

Or, 3 × 5 = - 4 + 5× c'

∴ 5 c' = 15 + 4

or, 5 c' = 19

Or, c' = $\frac{19}{5}$

So, The equation of line with slope $\frac{2}{5}$ and passing through points ( -2 , 3)

y = $\frac{2}{5}$ x + $\frac{19}{5}$

y = $\frac{2 x + 19}{5}$

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0

3 years ago

Use the definition of the derivative to differentiate f(x)= In x

WINSTONCH [101]

By def. of the derivative, we have for y = ln(x),

$\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac{\ln(x+h)-\ln(x)}{h}$

$\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac1h \ln\left(\frac{x+h}{x}\right)$

$\displaystyle \frac{dy}{dx} = \lim_{h\to0} \ln\left(1+\frac hx\right)^{\frac1h}$

Substitute y = h/x, so that as h approaches 0, so does y. We then rewrite the limit as

$\displaystyle \frac{dy}{dx} = \lim_{y\to0} \ln\left(1+y\right)^{\frac1{xy}}$

$\displaystyle \frac{dy}{dx} = \frac1x \lim_{y\to0} \ln\left(1+y\right)^{\frac1y}$

Recall that the constant e is defined by the limit,

$\displaystyle e = \lim_{y\to0} \left(1+y\right)^{\frac1y}$

Then in our limit, we end up with

$\displaystyle \frac{dy}{dx} = \frac1x \ln(e) = \boxed{\frac1x}$

In Mathematica, use

D[Log[x], x]

5 0

3 years ago

At a grocery store, 7 apples and 2 oranges will cost $12.80. In addition, 6 apples and 3

Pachacha [2.7K]

Answer:

Equation 1: 7x + 2y = 12.8

Equation 2: 6x + 3y = 12

Cost of 1 apple: $1.60

Cost of 1 orange: $0.80

Cost of 1 orange: $Step-by-step explanation:

Let's use the elimination method to solve this

Multiply equation 1 by 3

(7x + 2y = 12.8) x 3 = 21x + 6y = 38.4

Multiply equation 2 by -2

(6x + 3y = 12) x -2 = -12x - 6y = -24

The x terms will cancel each other out

21x + 6y = 38.4

-12x - 6y = -24

9x = 14.4

Divide by sides by 9 to isolate the x variable

9x/9 = 14.4/9

x = 1.6

This means an apple costs $1.60

Plug the new x into one of the original equations to find y; we'll use equation 1

7(1.6) + 2y = 12.8

11.2 + 2y = 12.8

Subtract 11.2 from both sides

11.2 + 2y = 12.8

- 11.2 - 11.2

2y = 1.6

Divide both sides by 2

2y/2 = 1.6/2

y = 0.8

This means an orange costs $0.80

4 0

3 years ago