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777dan777 [17]
3 years ago
14

A line is represented by the equation y/x-2=3/11. What are the coordinates of some points that line on the line?

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

y/x-2=3/11 would be easier to work with if we were to put it into a more standard form, e. g., y = mx + b.

First, add 2 to both sides, to isolate y/x:

y/x = 3/11 + 22/11 = 25/11.

Next, mult. both sides by x, to get y by itself:  y = (25/11)x.  

This is your function.

Now make a table.  You can choose any x values you want, and then calculate y for each one.

x   y

0  0

1   25/11

3  (25/11)*3 = 75/11

Then we have three points on this line: (0,0), (1, 25/11), 3, 75/11).  You could obtain more by choosing additional x values.

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What is the area of a sector with a central angle of 2pi/9 radians and a diameter of 20.6mm? Use 3.14 for Ali and round your ans
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- The area of the circle is:

 A=πr²

 A is the area of the circle.
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 r is the radius of the circle.

 - To calculate the area of <span> the sector indicated in the problem, you must apply the following formula:

 As=(</span>θ/2π)πr²

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 θ is the central angle (θ=2π/9)
 π=3.14
 r is the radius.

 - First, you must find the radius:

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 - Now, you can substitute the values into the formula As=(θ/2π)πr². Then, you have:

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 - Finally, the area of the sector is:

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