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3 years ago

Areas and perimeters

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

I think its the second one

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A sample of 15 recent college graduates found that starting salaries for attorneys in New York City had a mean of $102,342 and a

cricket20 [7]

Answer:

The average salary of all recently graduated attorneys in New York City, 102,342 dollars.

Step-by-step explanation:

n = 15

Starting salaries for attorneys in New York City had a mean of $102,342

Standard deviation = $21,756

$\mu$ represents the mean of the population

We are given that salaries for attorneys in New York City had a mean of $102,342

So, Option B is true

The average salary of all recently graduated attorneys in New York City, 102,342 dollars.

3 0

3 years ago

Answer The forth question I will give u 95 points and the brilliantist

Llana [10]

ANSWER:

60°

EXPLAINATION:

= 2r + θ/360°× 2 x 227 x 21

64 = 2 x 21 + θ/360° x 2 x 22/7 x 21

64 = 42 + θ/360° x 44 x 3

64 - 42 = θ/360° x 11 x 3

22 = 33θ/90

θ=22×30/11

= 60°

6 0

3 years ago

Read 2 more answers

Which inequality is a true statement?

Shtirlitz [24]

None, the only correct answer is...

-2 > -12

... in negative integers, the smaller the magnitude the bigger it is.

8 0

4 years ago

Jaden use Tony Curtis to make a design above the stove 15 out of 20 of his tires were green what is an equivalent fraction for t

ratelena [41]

Answer:

3/4

Step-by-step explanation:

15/20 = 3/4

5 0

3 years ago

What is k if : k!+48=48((k+1)^m)

lys-0071 [83]

Answer:

The value of k is greater than or equal to 0, i.e. k≥7.

Step-by-step explanation:

The given equation is

$k!+48=48((k+1)^m)$

The value of k must be a positive integer because k! is defined for k≥0, where k∈Z.

Subtract 48 from both the sides.

$k!=48((k+1)^m)-48$

$k!=48((k+1)^m-1)$

$k!=48(k+1-1)(\frac{(k+1)^m-1}{(k+1)-1})$

Using $[\frac{r^m-1}{r-1}=r^{m-1}+r^{m-2}+...+1]$ , we get

$k!=48k((k+1)^{m-1}+(k+1)^{m-2}+...+1)$

Divide both sides by 48k.

$\frac{k!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1$

$\frac{k(k-1)!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1$

$\frac{(k-1)!}{48}=(k+1)^{m-1}+(k+1)^{m-2}+...+1$

Note: The value of m can be 0 or 1.

The value of k is positive integer, so the right hand side of the above equation must be a positive integer.

Since RHS of the equation is positive integer, therefore (k-1)! is completely divisible by 48.

$k-1\geq 6$

Add 1 on both sides.

$k\geq 6+1$

$k\geq 7$

Therefore the value of k is greater than or equal to 0.

4 0

4 years ago

Areas and perimeters​

Areas and perimeters