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alisha [4.7K]
2 years ago
10

Which one is it? I will give you twenty points, if you will answer

Mathematics
2 answers:
nirvana33 [79]2 years ago
6 0
3/6. because 3 is half of 6 as 1 is half of 2.
denis-greek [22]2 years ago
3 0

Answer:

A fraction equivalent to \frac{1}{2} on the number line is \frac{3}{6}.

Drag the dot to \frac{3}{6} on the number line.

Step-by-step explanation:

3 is half of 6. To check if this is correct multiply \frac{1}{2} and 3.

\frac{1}{2}*3=\frac{3}{6}

Hope this helps!

If not, I am sorry.

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which explains the correct way to move the decimal point to find the quotient in the problem 12.46 divided by 100? My choices ar
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Well, since it has 2 zeros, you move the point 2 places to the right.
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3 years ago
Simplify the exptession 3m+(m+5)​
Alex17521 [72]

Answer:4m+5

Step-by-step explanation:

3m+m+5

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Help me fast or else you do not get a signed autograph from Jeffery Epstein!
MariettaO [177]
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Suppose there is this little town with a finite number of people: (1) No two inhabitants have exactly the same number of hairs.
Vadim26 [7]

The highest possible number of inhabitants in that little town are 743.

<h3>What are inhabitant?</h3>

A person or animal that lives in a place is called as the inhabitant.

Suppose there is this little town with a finite number of people: (1) No two inhabitants have exactly the same number of hairs. (2) No inhabitant has exactly 743 hairs or no hairs at all. (3) There are more inhabitants than there are hairs on the head of any inhabitant.

Let say there are 519 people in the town. and make them stand in a line with increasing number of hairs on their heads. This way, there will be a person on the last, who has no hair.

There are more number of people than the hairs. From bald to 742 hairs, 743 is the limit.

Thus, the highest possible number of inhabitants in that little town are 743.

Learn more about inhabitant.

brainly.com/question/15121341

#SPJ1

5 0
2 years ago
Pls help I don't know how to do this​
AVprozaik [17]

Answer:

Vertex, I believe.

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3 years ago
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