<span>(5x^7 y^2)(-4x^4 y^5) =-20x^a y^b
</span><span>
solve this:
(5x^7 y^2)(-4x^4 y^5)
= -20 x^(7 + 4) y^(2 + 5)
= -20 x^11 y^7
answer
</span>A) a=11, b=7
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
First you would solve for h(5) by plugging in 5 as your x, then solving it.
h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26
Next you would multiply the 26 by the individual h, which is basically h(1).
h(1) = 1^2 + 1
h(1) = 2
Lastly you multiply your h(1) value by the h(5) value to get your answer.
h(1) • h(5) = 26 • 2
h[h(5)] = 52
The answer to your question is x=-2y+4
Answer:
(a) 2min/15units
(b) 1min/20units
(c) The bottleneck stage is cutting. The process capacity is 450units/hour
(d) The capacity of the new employee should be 1unit/2sec. The process capacity will increase four times
Step-by-step explanation:
(a) Cycle time for stage cutting for 2 employees = 16sec/2units × 1min/60sec = 2min/15units
(b) Cycle time for stage sealing for 1 employee = 3sec/1unit × 1min/60sec = 1min/20units
(c) Process capacity of stage cutting = 15units/2min × 60min/1hour = 450units/hour
(d) If the capacity of the new employee is 1unit/2sec, the process capacity = 1unit/2sec × 3600sec/1hour = 1800units/hour. The process capacity increases 4 times (1800/450 = 4)