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3 years ago

For this question I know that the answer is C but how do I show work for the answer?

Mathematics

1 answer:

Alexandra [31]3 years ago

3 0

I'm not sure if there is a specific way you need to do this, but.....

You could do:

(x - 3)° = 74°

Because you know that the 2 lines are parallel and the angles should be the same

x - 3 = 74 Add 3 on both sides

x = 77°

A straight line is 180°. The angles (x - 3)°, 41°, and (y + 8)° make up this 180° angle, so you could do:

(x - 3) + 41 + (y + 8) = 180

Since you know the angle of (x - 3), you can replace (x - 3) with 74

74 + 41 + (y + 8) = 180

115 + y + 8 = 180

123 + y = 180 Subtract 123 on both sides

y = 57°

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Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I

sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

$speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)$

Back from the store:

$s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)$

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

$\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles$

∴ length of trip to the store = t₁

from eqn (1)

$t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours$

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3 years ago

How do you simplify 4^-2h^-4j^3

notka56 [123]

j^3
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when you have negatives, you want them to be positive. To do that you need to convert it into a fraction

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Answer:

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Step-by-step explanation:

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solving both for x

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h/tanα=h/tanß-88

h/tanß-h/tanα=88

(htanα-htanß)/(tanα*tanß)=88

h(tanα-tanß)/(tanα*tanß)=88

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Since α=32 and ß=22...

h=88(tan32*tan22)/(tan32-tan22)

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