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3 years ago

For this question I know that the answer is C but how do I show work for the answer?

Mathematics

1 answer:

Alexandra [31]3 years ago

3 0

I'm not sure if there is a specific way you need to do this, but.....

You could do:

(x - 3)° = 74°

Because you know that the 2 lines are parallel and the angles should be the same

x - 3 = 74 Add 3 on both sides

x = 77°

A straight line is 180°. The angles (x - 3)°, 41°, and (y + 8)° make up this 180° angle, so you could do:

(x - 3) + 41 + (y + 8) = 180

Since you know the angle of (x - 3), you can replace (x - 3) with 74

74 + 41 + (y + 8) = 180

115 + y + 8 = 180

123 + y = 180 Subtract 123 on both sides

y = 57°

You might be interested in

17+3.6 btw it's an decimal

inn [45]

The answer is 20.6 because 17+3=20 and then you add the decimal so 20+0.6= 20.6

5 0

3 years ago

Read 2 more answers

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance

alexgriva [62]

Answer:

96.512 °F < x < 591.242 °F

Step-by-step explanation:

We are given;

Melting point = 35.84 °C

Boiling point = 310.69 °C

Now, we are given that formula to convert °C to °F is;

°C = (5/9)°F

Thus if the temperature in Fahrenheit is x, then;

Melting point is; 35.84 °C = (5/9)x°F - "32"

x = ((9 × 35.84)/5) + 32

x = 96.512 °F

Similarly, for Boiling point;

Boiling point is;

310.69 °C = (5/9)x°F - "32"

x = ((9 × 310.69)/5) + 32

x = 591.242 °F

Now, we are told that matter is in its liquid form when it is between melting and boiling point.

Thus, range of x in inequality form is;

96.512 °F < x < 591.242 °F

6 0

3 years ago

(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).

Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = $\frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }$

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use product rule,i.e., $\frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}$

this will give k'(x)=f'(x)g(x) + f(x)g'(x)

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ $m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)}$ ]. Since m(x) has a function g(x) in the denominator so we need to use division rule to differentiate m(x). Division rule is as follows : $\frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}$