If the 2 after the parentheses is a squared, then your answer would be y=3x^2-12x+10. but if it is just a regular 2, your answer would be 6x-y=14
Answer:
The measure of the third angle is 117 degrees and the measure of the two equal angles is 31.5 degrees
Step-by-step explanation:
<u><em>The correct question is</em></u>
A geodesic dome is compromised of two different types of triangular panels. One of these is an isosceles triangle. In one geodesic dome, the measure of the third angle is 85.5 degrees more than the measure of either of the two equal angles. Find the measure of the three angles
we know that
An isosceles triangle has two sides and two equal interior angles
Let
x -----> the measure of the third angle
y ----> the measure of either of the two equal angles
we know that
-----> equation A
-----> equation B
substitute equation B in equation A and solve for y
therefore
The measure of the third angle is 117 degrees and the measure of either of the two equal angles is 31.5 degrees
2149 seats. Since 2149 rounds down to 2100 at the nearest hundred, this is the greatest amount of seats possible in the stadium. If there were 2150 seats, it would round to 2200 seats, so 2149 seats is the correct answer.
Hope this helps!
Answer:
The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.
One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):
P(X=k)=(Kk)(N−Kn−k)(Nn)
where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.
P(X=2)=(42)(480)(522)
P(X=2)=61326=1221
In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.
Another way is using simple probabilities and combinations:
P(X=2)=(4C1∗152)∗(3C1∗151)
P(X=2)=452∗351=1221
The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.
Step-by-step explanation:
Answer:
(24, 32, 40) is a Pythagorean triplet.
Option A) Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.
Step-by-step explanation:
We are given the following in the question:
Pythagorean triplet: (3,4,5)
New Pythagorean triplet obtained = (24, 32, 40)
Pythagoras theorem:
For a right angles triangle the sum of square of sides of triangle is equal to the square of hypotenuse of triangle.
Verification:
Yes, Tessa is correct.
(24, 32, 40) is a Pythagorean triplet.
Pythagorean triple be created using multiplies of a known Pythagorean triple
Option A) Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.