How did bill spend longer .. days ... ? what
54<span> is </span><span>bisected hope this helps
</span>
Answer: The climb angle is 14°
Step-by-step explanation:
We can create a rectangle triangle, where the velocity of the plane is the hypotenuse, the horiontal component (1000 ft by unit of time) is a cathetus and the vertical component is (250ft by unit of time).
We want to find the angle that is adjacent to the horizontal component, so we can use the relationship.
Tan(angle) = opposite cathetus/adjacent cathetus
Tan(angle) = 250/1000 = 1/4
Angle = Atan(1/4) = 14°
$\sec x=\frac1{\cos x}$
$\therefore \cot^2x\cdot\sec^2x= \frac{\cos^2x}{\sin^2x}\frac{1}{\cos^2x}=\frac{1}{\sin^2x}$
