All categories

3 years ago

HELP ME PLEASE!!! I NEED HELP!

Mathematics

2 answers:

alexandr1967 [171]3 years ago

5 0

For the whole numbers:

erma4kov [3.2K]3 years ago

4 0

1. 24 and 23.8

2. 26 and 25.7

3. 23 and 22.8

4. 25 and 24.8

5. 21 and 20.9

6. 46 and 46.3

7. 64 and 63.7

8. 56 and 56.5

9. 75 and 74.6

10. 91 and 90.7

When rounding, whether it's a whole number or a decimal, you would round up if the number next to it is 5 and up. You wouldn't change the number next to it if it's below 5.

If you have any further question, please reach out to me :)

You might be interested in

Kelly earns $178.50 in interest on an account that earns simple interest at a rate of 4%. If she kept the money in the account f

Otrada [13]

Answer:

$892.50

Step-by-step explanation:

The amount of interest earned is given by ...

I = Prt

Filling in the given values, we have ...

$178.50 = P·0.04·5

Dividing by 0.20 gives ...

$178.50/0.20 = P = $892.50

The principal amount in Kelly's account is $892.50.

7 0

2 years ago

7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

Juliette [100K]

Answer:

A) JK and AB =

$[tex] \boxed{( \theta) = \f{12}{( \theta)} }$ So, =》 $\dfrac{10}{5} = \dfrac{1}{ \( \theta) }$ =》 $\( \theta) = \dfrac{5}{2}$ [/tex]

B) AABC

$[tex] \boxed{( \theta) = {1}{( \theta)} }$ So, $23}{-18=\\Ans } \boxed$

C) AABM:

$[tex] e \fbox{: }$ The value of k for which $\sin(jm) = \cos(x)$ is $\dfrac{\p}{2}$ ans[/tex]

----------

3 0

3 years ago

Joaquin is constructing the perpendicular bisector of ab. What should be his first step?

natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of $\over{AB}$ .

Step-by-step explanation:

To construct a perpendicular for $\over{AB}$ , we must first take a compass & take the distance of its arms wider than half the length of $\over{AB}$ .

This is done in order to get two intersecting arcs in the top & bottom of $\over{AB}$ so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above $\over{AB}$ , draw a line joining these 2 points through their points of intersection. The point where it intersects $\over{AB}$ is the middle-most point of $\over{AB}$ & now a perpendicular bisector of $\over{AB}$ is constructed.

$\rule{150pt}{2pt}$

3 0

1 year ago

I need help with these questions

inysia [295]

Answer:

28. m<A=20°, m<B=70°

32. m<A=103°, m<B=77°

Step-by-step explanation:

complementary angle=a+b=90°

supplementary angle=a+b=180°

28. A+B=90°

5x+17x+2=90°

22x+2=90°

22x=90-2

22x=88

22x/22=88/22

x=88/22=4

m<A=5x=5*4=20°

m<B=17x+2=17*4+2=68+2=70°

Check

A+B=90°

20+70=90°

90°=90°

32. A+B=180°

x+11+x-15=180°

2x-4=180°

2x=180+4

2x=184

2x/2=184/2

x=184/2

x=92

m<A=x+11=92+11=103°

m<B=x-15=92-15=77°

Check

A+B=180°

103+77=180°

180°=180°

6 0

2 years ago

Review: 5 Step Problem Solving Matching

Jobisdone [24]

Answer:

1. Identify problem 2. Identify plan 3. what might happen... 4.work the strategy

5.Measure can i have brainiest

Step-by-step explanation:

5 0

2 years ago

HELP ME PLEASE!!! I NEED HELP!​

HELP ME PLEASE!!! I NEED HELP!