0 × <span>0 = 0
0 </span>× <span>1 = 0
1 </span>× <span>1 = 1
Which means multiplication is closed under {0, 1}
</span><span>1 </span>÷ <span>1 = 1
0 </span>÷ <span>1 = 0
</span>
Division is not closed under {0, 1}
1 + 1 = 2
Addition is not closed under {0, 1}
0 - 1 = -1
Subtraction is not closed under {0, 1} either
So it's only A. Multiplication which is closed under {0, 1}
The answer is 12>x>-7
Step-by-step explanation:
it's first divided into 2 parts
1 . 15 > 2x - 9
2. 2x - 9 > -23
Then solve them individually.
let's do it,
<u>First half</u>
15 > 2x - 9
15+9 > 2x
24 > 2x
24/2 > x
12>x
<u>Second half</u>
2x-9>-23
2x>-23+9
2x>-14
x>-14/2
x>-7
<u>Joining of the two halves</u>
We have :
12>x>-7
B. (6, -8)
First, you need to figure out the slope of the line
(y1 - y2) / (x1 - x2)
After substituting points D(-3, 4) A(3, -4)
[4 - (-4)] / (-3 - 3)
(8) / (-6)
The slope of the line is -8/6 or -4/3 simplified
Then you can put it in point slope form:
(y - y1) = m(x - x1)
(y - y1) = -4/3(x - x1)
The point that I am using for point slope form is A(3, -4)
[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)
Next you have to simplify the equation so that y is isolated
y + 4 = -4/3(x - 3)
First distribute the -4/3
y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4
Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x
Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal
For example) (6, -8)
-8 = -4/3(6)
-8 = -8
So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D
~~hope this helps~~
Answer:
y=2, x=-1
Step-by-step explanation:
We can add the two equations together to eliminate x:
6x+5y+(-6x)+7y=4+20
12y=24
y=2
We plug y into the first equation and get
6x+5(2)=4
6x+10=4
6x=-6
x=-1
