Answer:
7m^2 - 11m - 2
Step-by-step explanation:
Subtract (-3m^2 + 10m + 4) from 4m^2 - m + 2:
4m^2 - m + 2
- (-3m^2 + 10m + 4) Now distribute the negative sign:
4m^2 - m + 2
+ 3m^2 - 10m - 4
--------------------------
7m^2 - 11m - 2 is the final answer.
Answer:
11 - 4x
Step-by-step explanation:
-5 - 3x - x - (-16)
Reorder the terms so that like terms are next to each other
-5 - (-16) - 3x - x
Combine like terms
11 - 4x
(ax + b)/c ≤ b
ax+b ≤ cb
ax ≤ cb - b
x ≤ (cb-b)/a
777 divided by 21 = 34 with a remainder of 3
This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
