Answer:
The geometric mean of the measures of the line segments AD and DC is 60/13
Step-by-step explanation:
Geometric mean: BD² = AD×DC
BD = √(AD×DC)
hypotenuse/leg = leg/part
ΔADB: AC/12 = 12/AD
AC×AD = 12×12 = 144
AD = 144/AC
ΔBDC: AC/5 = 5/DC
AC×DC = 5×5 = 25
DC = 25/AC
BD = √[(144/AC)(25/AC)]
BD = (12×5)/AC
BD= 60/AC
Apply Pythagoras theorem in ΔABC
AC² = 12² + 5²
AC² = 144+ 25 = 169
AC = √169 = 13
BD = 60/13
The geometric mean of the measures of the line segments AD and DC is BD = 60/13
Answer:
17
Step-by-step explanation:
Answer:
248 degrees
Step-by-step explanation:
Since segment PL is congruent to segment LK, their corresponding arcs are also congruent. Knowing this, we can set 11x - 10 and 9x + 2 equal to each other:
11x - 10 = 9x + 2
2x = 12
x = 6.
So, plugging in 6 into the value of x for both minor arcs gives us that arc PMK is 112 degrees. Since the whole circle is 360 degrees, major arc PNK is 360 - 112 = 248 degrees.
Hope that helped! :)
Answer:
<h2>600 km</h2><h2 />
Step-by-step explanation:
<u>400 km</u> = <u> x </u>
6 min 9 min
cross multiply:
6x = 400 ( 9)
x = 3600 / 6
x = 600 km
Answer:
b
Step-by-step explanation: