Ask question

Ask question

All categories

3 years ago

6

What type of dilation is formed when the scale factor K is greater than one

1 answer:

Novay_Z [31]3 years ago

6 0

Answer:

Enlargement

Step-by-step explanation:

When k > 1, the dilation is an enlargement. When k > 0 and k < 1, the dilation is a reduction. In a dilation, the original figure and its image are similar. The ratio of the side lengths of the image to the corresponding side lengths of the original figure is the scale factor of the dilation.

You might be interested in

Select the correct answer.

Jet001 [13]

The answer would be A. 5

8 0

2 years ago

Read 2 more answers

There are 125 students in sixth grade. 2/3 of the sixth graders ride the bus. How many sixth graders ride the bus?

Luden [163]

125 ÷ 3 = 41.6666666667

41.66666666667 X 2
= 83.3333......
Technically not correct, because you cannot split sixth graders into pieces, so you would probably round it to 84 students.

3 0

3 years ago

Sales in Tiffin ties declined from 420 in last year to 360. What percentage drop is that

drek231 [11]

Answer:

14.29%

Step-by-step explanation:

<h3>Given</h3>

Initial sales = 420
Later sales = 360

<h3>Solution</h3>

<u>Drop in sales </u>

420 - 360 = 60

<u>Percentage drop </u>

60/420*100% = 14.29%

5 0

4 years ago

Please help with these questions. Will mark brainliest!

andrew11 [14]

Answer:

1, pre image 2, transformation

Step-by-step explanation:

6 0

3 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago