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Nataly_w [17]
3 years ago
6

What type of dilation is formed when the scale factor K is greater than one

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

Enlargement

Step-by-step explanation:

When k > 1, the dilation is an enlargement. When k > 0 and k < 1, the dilation is a reduction. In a dilation, the original figure and its image are similar. The ratio of the side lengths of the image to the corresponding side lengths of the original figure is the scale factor of the dilation.

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Hii, please help me w this :(( tysm
Ipatiy [6.2K]

Answer:

7. y

=

−

1

/2

x  +  4

8.  y= (0,4)

Step-by-step explanation:

7. the slope is -1/2 and the y intercept is 4

8. so basically, the y intercept is when y is zero, which makes this one (0,4)

HOPE THIS HELPS HAVE A GREAT DAY!!!  IM procrastinating chem doing this lolz

6 0
3 years ago
Mr. Mandel gave his class 12 minutes to read. 5 1/2 pages in that time. At what rate, in pages per hour, did Claire read?
Eva8 [605]
5 1/2 pages in 12 minutes.
11/2 pages in 12 minutes 

How many pages in an hour?
well, an hour has 60 minutes

Let's write a proportion
11/2 / 12 = x/60
cross multiply
(11/2 * 60) = 12x
330 = 12x
divide both sides by 12
27.5 or 27 1/2 = x

27.5 pages per hour.

Hope this helps
8 0
3 years ago
Can you please send me an example for this question <br> (15 ÷ 5 + 6 + 9) x 4 x 2 + 7
Mkey [24]
The answer is 88 hope that helped
3 0
3 years ago
Read 2 more answers
The equation of motion for a weight suspended from a particular spring is given by p(t)=2sint3+5cost3p(t)=2sin⁡t3+5cos⁡t3, where
daser333 [38]
The given displacement at time, t, is
p(t) = 2 sin(t³) + 5 cos(t³)

The initial equilibrium position is
p(0) = 5

To determine future equilibrium postions, define
f(t) = p(t) - 5 = 2 sin(t³) + 5 cos(t³ - 5
The derivative of f(t) is
f'(t) = (3t²)[2 cos(t³) - 5sin(t³)]

Equilibrium is established when f(t) = 0.
To solve this equation numerically, we shall use the Newton-Raphson method, given by.
t(n+1) = t(n) - f[t(n)]/f'[(t(n)], n=0,1,2, ...,

As a guess, let (0) = 1.
The iterative solution for t is shown below.

  n         t(n)
 ---   -----------
   0   1.0000
   1    0.9344
   2   0.9147
   3   0.9130
   4   0.9130

The solution converges rapidly to t = 0.913 s.
The graphical solution (shown below) confirms the numerical solution.

Answer:
The weight first reaches the equilibrium position in 0.913 sec.

4 0
3 years ago
Write an algebraic expression with the variable x that has a value of 3 when evaluated
kari74 [83]
X=23

(x+5) - 25 = 3?

If this is what you mean.
7 0
3 years ago
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