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Y_Kistochka [10]
2 years ago
11

1.hi students I have a question for you

Mathematics
1 answer:
katen-ka-za [31]2 years ago
6 0

Answer:

the answer of given question is $400.

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What is the sum of two numbers a and b decreased by their product?
belka [17]

The sum of two numbers a and b decreased by their product is (a+b)-ab

Step-by-step explanation:

Given the two numbers as a and b

Sum of these two numbers is a+b

The product of the two numbers is a*b, ab

The sum of the two numbers decreased by their product will be;

(a+b)-ab

Learn More

  • https://brainly.in/question/6082654
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Keywords : sum of two numbers, product

#LearnwithBrainly

8 0
3 years ago
hii how are yall doing me im ok ig.... i.dk anymore also plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help ty
lora16 [44]

Answer:

Step-by-step explanation:

j=+

We move all terms to the left:

j-(+)=0

We add all the numbers together, and all the variables

j-0=0

We add all the numbers together, and all the variables

j=0

   

7 0
3 years ago
Help me with this question plzzzz
zubka84 [21]
V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==
5 0
3 years ago
I need help people get brailestttt
vova2212 [387]

Answer:

Whats the question?

Step-by-step explanation:

7 0
2 years ago
Which expression is equivalent to (8^2)^-4
xz_007 [3.2K]

Answer:

C: \frac{1}{8*8*8*8*8*8*8*8}

Step-by-step explanation:

a^{-n} = \frac{1}{a^n}

Since a = 8^2 :

(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}

Since n = 4 :

(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}

6 0
2 years ago
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