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g100num [7]
3 years ago
6

10. Is it possible to draw a three-sided figure where two of the sides are equivalent and two of the angles

Mathematics
1 answer:
Goryan [66]3 years ago
5 0
The anwser is no its not possible
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Christine's middle school total of 900 students and 45 teachers. The local high school has 110 teachers and a student-teacher ra
sineoko [7]

Answer:

2,200

Step-by-step explanation:

From the above, we were given that;

Total students in Christine's middle school = 900

Teachers in Christine's middle school = 45 teachers

Local high school = 110 teachers

Then, we can write an equation ratio and solve it.

900 students / X = 45 teachers / 110 teachers

If we cross multiply, we'll get

900 × 110 = 45 × X

45X = 99,000

Divide both sides by 45

45X/45 = 99,000/45

X = 2,200

Therefore, Christine would find 2,200 students when she gets to high school.

4 0
3 years ago
erica purchased 2 Celtics season tickets for $4,000. the Celtics allowed her to pay this off in monthly installments of $444.25.
Semenov [28]
444.25(8) = 3554

4000 - 3554 = 446 <== what she still owes
7 0
3 years ago
HURRY I NEED IT FOR 3rd GRADE MATH<br><br> Whats 73 + 82
Bumek [7]

Answer:

155

Step-by-step explanation:

7 0
2 years ago
The amount of money Jose spends on movie tickets varies directly with the number of tickets he purchases.
zzz [600]

7 movie tickets :)

First, we must find the unit price:

20.25/3=6.75

Now we divide:

47.25/6.75=7

I hope you are having a great day, buddy :)

Please mark me as brainliest:)

7 0
3 years ago
Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average
hichkok12 [17]

Answer:

Section A = 18

Section B = 288

Section B is 16 times greater than A

Step-by-step explanation:

Given the function :

g(x) = 6(4)^x

x = 0 to x = 1

At x = 0

g(0) = 6(4)^0 = 6(1) = 6

At x = 1

g(1) = 6(4)*1 = 24

Average rate of change for Section A = g(1) - g(0) = 24 - 6 = 18

Section B ;

x = 2 ; x = 3

g(x) = 6(4)^x

x = 2 to x = 3

At x = 2

g(0) = 6(4)^2 = 6 * 16 = 96

At x = 3

g(1) = 6(4)^3 = 6(4*4*4) = 384

Average rate of change for Section B = g(3) - g(2) = 384 - 96 = 288

Number of times B is greater than A

Section B / section A = 288 / 18 = 16 times

3 0
3 years ago
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