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g100num [7]
3 years ago
6

10. Is it possible to draw a three-sided figure where two of the sides are equivalent and two of the angles

Mathematics
1 answer:
Goryan [66]3 years ago
5 0
The anwser is no its not possible
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F(x)=-x+9<br> That’s it I just need someone to help me with my math homework
Vilka [71]
X intercept is (9,0)
Y intercept is (0,9)
Pls mark me as brainliest
7 0
3 years ago
Haryati had 1250 oranges.
Blababa [14]
First you subtract 242 from 1250 which gives you 1080. Then you divide it by 8 which gives you 126. Multiply this value by 3 and this shows that Haryati received $378. Hope this is helpful.
7 0
3 years ago
Madison, Natalie, Isabella and Rebecca go shopping. Madison spent 4/5 of her money, Natalie spends 75% of her money,Isabella spe
BartSMP [9]

Answer:

you need common denominater so 10/10 - 9/10 =1/10 thats how much of her money she used.

Step-by-step explanation:

4 0
3 years ago
Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3
34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

{ \sin}^{2} (x) =  \frac{1}{2}

This implies that;

\sin(x) = \pm  \frac{ \sqrt{2} }{2}

If

\sin(x) = \frac{ \sqrt{2} }{2}

x =  \frac{\pi}{4}

in the first quadrant

x =  \frac{3\pi}{4}

in the second quadrant.

If

\sin(x) = -  \frac{ \sqrt{2} }{2}

x =  \frac{5\pi}{4}

in the third quadrant

x =  \frac{7\pi}{4}

5 0
3 years ago
Solve the Equation. 20x + 12 ≥ 14x + 30 A. x ≥ 7 B. x ≤ 7 C. x ≥ 3 D. x ≤ 3
Tamiku [17]

Answer:

x≥3

Step-by-step explanation:

Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)

8 0
4 years ago
Read 2 more answers
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