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3 years ago

Which relation is not a function? Reporting wrong answers.

Mathematics

1 answer:

Aleks [24]3 years ago

6 0

Answer:

C im pretty sure dont report me tho

Step-by-step explanation:

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Allana used Fraction 3 over 5 yard of fabric to make a scarf. Can she make 2 of these scarves with Fraction 1 and 7 over 10 yard

Paul [167]

(1 7/10) / (3/5)
(17/10) / (3/5) =
17/10 * 5/3 =
85/30 =
2 5/6........yes, because 1 7/10 divided by 3/5 = 2 5/6...answer C

5 0

3 years ago

Find the missing side of each triangle. Round your answers to the nearest 2 points tenth if necessary 8 6. X

notsponge [240]

Answer:

vwgshsbbdbdbgsgsvbshdbzvbzvzvz vs vs zvjdnbsndjjshshhshshbhbbsnsndbbdbdbdbdbbdbdbdbbdbdbsnjehhebejdjhshhdhehsbjsg...bsbbsbshhshs

hshhehebehhejeksjjsjaj

bhehgshz

dbshbsbbbhhghhbgqshjsudhebrhdhdhndksgwtsh

svvsbsbsbbshsbsggeggsg

Step-by-step explanation:

vwgshsbbdbdbgsgsvbshdbzvbzvzvz vs vs zvjdnbsndjjshshhshshbhbbsnsndbbdbdbdbdbbdbdbdbbdbdbsnjehhebejdjhshhdhehsbj

sg...bsbbsbshhshshshhehebehhejeksjjsjaj

bhehgs

hzbdbshbsbbbhhghhbgqshjsudhebrhdhdhndksgwtshsvvsbsbsbbshsbsggeggsg

5 0

3 years ago

U.S. postal regulations require that a package can have a maximum combined length and girth (distance around) of 108 in. A shipp

Eduardwww [97]

Answer: The maximum length that can be used is 56 inches.

Step-by-step explanation:

Since we have given that

Width of package = 14 inch

Height of package = 12 inch

Let the length of package be 'l'.

Combined length and girth i.e. distance around = 108 inches.

So, According to question, we get that

$l+2(w+h)=108\\\\l+2(14+12)=108\\\\l+2\times 26=108\\\\l+52=108\\\\l=108-52\\\\l=56\ inches$

Hence, the maximum length that can be used is 56 inches.

4 0

4 years ago

How do I turn 0.175 into percentage

frosja888 [35]

Moves the decimal over two places to the right and that will be your percentage.

6 0

3 years ago

The number of major faults on a randomly chosen 1 km stretch of highway has a Poisson distribution with mean 1.7. The random var

tiny-mole [99]

The probability can be modeled using the following formula:
$P(X =3)$
wherein X follows the density
$P(X=k)=\frac{1.7^ke^{-1.7}}{k!}$
Now for k = 3 we get:
$P(X=3)=\frac{1.7^3e^{-1.7}}{3!}=0.15$
The probability we are looking for is 0.15.
Do you have any question ?

6 0

3 years ago