9514 1404 393
Answer:
k = -1
Step-by-step explanation:
Put the given value of x in the equation, and solve the resulting equation for k.
2(5 -3) +k(1 +2·5) = k - 5 - 1
2(2) +k(11) = k -6 . . . . simplify a bit
10k = -10 . . . . . . . . . . add -4-k to both sides
k = -1 . . . . . . . . . . . . . divide by 10
The value of k is -1.
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<em>Check</em>
Use k = -1 in the original equation and solve for x.
2(x -3) -(1 +2x) = -1 -x -1
2x -6 -1 -2x = -x -2 . . . . eliminate parentheses
x = 7 -2 = 5 . . . . . . add x+7; answer checks OK
Answer:
Increasing on it's domain 
because the slope is positive.
The domain and range are both all real numbers, also known as
.
Step-by-step explanation:
All domain really means is what numbers can you plug in and you get number back from your function.
I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.
The domain is all real numbers.
In interval notation that is .
Now the range is the set of numbers that get hit by y=3x+2.
Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.
If slope is positive, then the line is increasing.
If slope is negative, then the line is decreasing.
So y=3x+2 hits all values of y because it is increasing forever. The range is all real numbers. In interval notation that is .
The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours
<h3>What is an equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let a represent the time flown by the goose and b represent the time flown by the heron. Hence:
a + b = 14 (1)
Also:
20a + 10b = 180 (2)
From equation 1 and 2:
a = 4, b = 10
The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours
Find out more on equation at: brainly.com/question/2972832
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Answer:
Step-by-step explanation:
trapezium
<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>
The answer would defintley be 69 if you want the right answer.
