Which relation is not a function? Reporting wrong answers.

Given line l and line M are parallel. Find the value of x and y.

Liula [17]

Answer:

x = 4

y = 10

Step-by-step explanation:

29x - 3 + 15x + 7 = 180 (Linear Pair)

44x + 4 = 180

44x + 4 = 180 - 4

44x = 176

$\frac{44x}{44} = \frac{176}{44}$

x = 4

29(4) - 3

116 - 3

113

13y - 17 = 113 (Alternate Exterior Angles Theorem)

13y - 17 + 17= 113 + 17

13y = 130

$\frac{13y}{13} = \frac{130}{13}$

y = 10

6 0

3 years ago

Find the simplified product b-5/2b x b^2+3b/b-5

White raven [17]

Answer:

The product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

Step-by-step explanation:

Given expression $\frac{b-5}{2b}$ and $\frac{b^2+3b}{b-5}$

We have to find the product of $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Consider the given expression $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Multiply fractions, we have,

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}$

Cancel common factor ( b - 5 )

we have, $=\frac{b^2+3b}{2b}$

Apply exponent rule,

$\:a^{b+c}=a^ba^c$

$b^2=bb$

$=bb+3b=b(b+3)$

$=\frac{b\left(b+3\right)}{2b}$

Cancel common factor b , we have,

$=\frac{b+3}{2}$

Thus, the product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

8 0

3 years ago

Read 2 more answers

Which equations could you use the division property of equality to solve?

disa [49]

Answer:

2.35y = 4.70

4 = 10w

55x = 111

Step-by-step explanation:

Hi, the division property of equality states that if we divide both sides of an equation by a non-zero number, the equality remains. (Both sides remain equal).

So, the equations that we have to use the division property of equality to solve are:

2.35y = 4.70

Dividing both sides by 2.35:

2.35y /2.35= 4.70/2.35

y= 2

4 = 10w

4/10=10w/10

0.4=w

55x = 111

55x/55 =111/55

x = 111/55

3 0

3 years ago

Read 2 more answers

10 points-I need help ASAP please someone help

leonid [27]

Answer:

6.36 m

Step-by-step explanation:

The length of the tree's shadow is 7 m + 1.8 m = 8.8 m. Tanya's height is 1.3/1.8 times the length of her shadow. The tree height is, likewise, 1.3/1.8 times the length of its shadow, so is ...

tree height = (1.3/1.8)×(8.8 m) ≈ 6.36 m

The tree is about 6.36 m tall.

3 0

3 years ago

Starting at home Nadia traveled uphill to the grocery store for 30 minutes at just 4mph. She then traveled back home along the s

xz_007 [3.2K]

Answer:

6 mph

Step-by-step explanation:

Here is the complete question: Starting at home Nadia traveled uphill to the grocery store for 30 minutes at just 4mph. She then traveled back home along the same path downhill at a speed of 12 mph. What is her average speed for the entire trip from home to the grocery store and back?

Given: Time taken to travel uphill to the grocery store is 30 minutes.

Speed of travelling uphill to the grocery store is 4 mph.

Speed of travelling downhil to the home is 12mph.

First converting the unit if time given:

Time taken to travel uphill to the grocery store= $\frac{30}{60} = \frac{1}{2}$