Based on the data, the median time it takes players to complete the game is 1148 minutes.
<h3>What is the median?</h3>
It is the mathematical value that is the middle when values are sorted.
<h3>How to find the median time?</h3>
457 - 548- 866 - 952 - 976 - 1037 - 1148 - 1235 - 1245- 1431-1486 - 1759 - 1864
Identify the value of the middle
Considering there are 13 values, the value of the middle is the value number 7 or 1148.
Note: This question is incomplete because the data is missing, below I attached the missing section,
Learn more about median time in: brainly.com/question/7493103
Answer:
Step-by-step explanation:
Let x represent the number of units of games sold.
The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $6200. It means that the total variable cost for x units would be
0.9 × x = 0.9x
The inventor sells each game for $1.69. This means that the total revenue from x units of games sold would be
1.69 × x = 1.69x
The total cost for a business is the sum of the variable cost and the fixed costs. Therefore, the total cost for the number of games sold would be
C = 6200 + 0.9x
Profit = Revenue - total cost
Therefore,
Profit = 1.69x - (6200 + 0.9x)
= 1.69x - 0.9x - 6200
= 0.79x - 6200
Answer:
The slope of the line is 10
Step-by-step explanation:
To find the slope, simply identify 2 points on the line. I chose: (1,10) and (2,20)
20-10=10
2-1=1
The slope of the line is 10
To check this answer, just multiply X with 10 and you will always get Y!
Answer:
We have the measures:
1023 cm
2.3 m
8.72m
6430 mm
1200 mm
6.4 cm
2.5m
0.06km
Now let's write all those measures in the same unit, let's use meters.
We know that:
1cm = 0.01m
1mm = 0.001m
1 km = 1000m
Then, we can rewrie the measures as:
1023 cm = 1023*0.01 m = 10.23 m
2.3 m
8.72m
6430 mm = 6430*0.001 m = 6.430 m
1200mm = 1200*0.001 m = 1.2 m
6.4 cm = 6.4*0.01m = 0.064 m
2.5m
0.06km = 0.06*1000km = 60m
Then the order, from smallest to largest is:
6.4 cm
1200mm
2.3 m
2.5m
6430 mm
8.72m
1023 cm
0.06km
