Answer:
91.4
Step-by-step explanation:
Answer:
option 4
Step-by-step explanation:
(f*g)(x) =(x² + x+ 1)*(x² - x -1)
= x²*(x² - x -1) + x(x² - x -1) + 1*( x² - x -1)
= x²*x² - x²*x -x²*1 + x*x² - x*x -x*1 + x² - x -1
= x⁴ - x³ - x² +x³ - x² - x + x² - x -1
= x⁴ - x³ + x³ - x² - x² + x² - x - x - 1
= x⁴ - x² - 2x - 1
Since <span><span>2x,</span><span>2x</span></span> does not contain the variable to solve for, move it to the right side of the equation by subtracting <span><span>2x,</span><span>2x</span></span> from both sides.<span><span><span>−y</span>=<span><span><span>−2</span>x</span>+9</span></span><span><span>-y</span>=<span><span><span>-2</span>x</span>+9</span></span></span>Multiply each one <span><span><span>−y</span>=<span><span><span>−2</span>x</span>+9</span></span><span><span>-y</span>=<span><span><span>-2</span>x</span>+9</span></span></span> by <span><span>−1</span><span>-1</span></span>Multiply each one in <span><span><span>−y</span>=<span><span><span>−2</span>x</span>+9</span></span><span><span>-y</span>=<span><span><span>-2</span>x</span>+9</span></span></span> by <span><span>−1</span><span>-1</span></span>.<span><span><span><span>−y</span>⋅<span>−1</span></span>=<span><span><span><span>−2</span>x</span>⋅<span>−1</span></span>+<span>9⋅<span>−1</span></span></span></span><span><span><span>-y</span>⋅<span>-1</span></span>=<span><span><span><span>-2</span>x</span>⋅<span>-1</span></span>+<span>9⋅<span>-1</span></span></span></span></span>make it simple <span><span><span>−y</span>⋅<span>−1</span></span><span><span>-y</span>⋅<span>-1</span></span></span>.Multiply some more. <span><span>−1</span><span>-1</span></span> by <span><span>−1</span><span>-1</span></span> to get <span>11</span>.<span><span><span>1y</span>=<span><span><span><span>−2</span>x</span>⋅<span>−1</span></span>+<span>9⋅<span>−1</span></span></span></span><span><span>1y</span>=<span><span><span><span>-2</span>x</span>⋅<span>-1</span></span>+<span>9⋅<span>-1</span></span></span></span></span>Multiply <span>yy</span> by <span>11</span> to get <span>yy</span>.(but Y?)<span><span>y=<span><span><span><span>−2</span>x</span>⋅<span>−1</span></span>+<span>9⋅<span>−1</span></span></span></span><span>y=<span><span><span><span>-2</span>x</span>⋅<span>-1</span></span>+<span>9⋅<span>-1</span></span></span></span></span>Simplify each stuff that you simplify. Multiply...again..... <span><span>−1</span><span>-1</span></span> by <span><span>−2</span><span>-2</span></span> to get <span>22</span>.<span><span>y=<span><span>2x</span>+<span>9⋅<span>−1</span></span></span></span><span>y=<span><span>2x</span>+<span>9⋅<span>-1</span></span></span></span></span>Multiply some more..... <span>99</span> by <span><span>−1</span><span>-1</span></span> to get <span><span>−9</span><span>-9</span></span>.<span>y=<span><span>2x</span><span>−<span>9.</span></span></span></span>
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.