Answer:

Step-by-step explanation:
Let

We factor 2 to obtain;

We factor the polynomial within the parenthesis by grouping.



We apply difference of two squares on the second factor: 

We now compare to;

It is now obvious that 
The expression for the number of segments drawn out of the n number of points in the circle is,
n² / 2 - n / 2
Substituting directly to the expression the number of points, n, which is equal to 8,
8² / 2 - 8 / 2 = 28
Thus, there are 28 segments that can be drawn from the points.
Answer:
all real values of x where x < -1
Step-by-step explanation:
See attached graph.