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Arlecino [84]
3 years ago
13

A rectangular section of wilderness will be set aside as a new wildlife refuge. Its dimensions are 6 x 10^5 meters by 5 x 10^4 m

eters. Find the area of the land in square meters by 5 x 10^4 meters. Find the area of the land in the square meters. Make sure your answer is in correct scientific notation form and show your work.
Thanks.
Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

area is length * width, so

5x10^5 * 4x10^4

multiplication is commutative, so that's

5*4 * 10^5*10^4

= 20 * 10^9

= 2*10^10 m^2

if the powers stuff is confusing, it's just shorthand for multiplication

10^5*10^4 = (10*10*10*10*10)*(10*10*10*10) = 10^9

just as multiplication is shorthand for addition

5*4 = 5+5+5+5

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An industrial psychologist conducted an experiment in which 40 employees that were identified as "chronically tardy" by their ma
iren [92.7K]

Answer:

The probability plot of this distribution shows that it is approximately normally distributed..

Check explanation for the reasons.

Step-by-step explanation:

The complete question is attached to this solution provided.

From the cumulative probability plot for this question, we can see that the plot is almost linear with no points outside the band (the fat pencil test).

The cumulative probability plot for a normal distribution isn't normally linear. It's usually fairly S shaped. But, when the probability plot satisfies the fat pencil test, we can conclude that the distribution is approximately linear. This is the first proof that this distribution is approximately normal.

Also, the p-value for the plot was obtained to be 0.541.

For this question, we are trying to check the notmality of the distribution, hence, the null hypothesis would be that the distribution is normal and the alternative hypothesis would be that the distribution isn't normal.

The interpretation of p-valies is that

When the p-value is greater than the significance level, we fail to reject the null hypothesis (normal hypothesis) and but if the p-value is less than the significance level, we reject the null hypothesis (normal hypothesis).

For this distribution,

p-value = 0.541

Significance level = 0.05 (Evident from the plot)

Hence,

p-value > significance level

So, we fail to reject the null or normality hypothesis. Hence, we can conclude that this distribution is approximately normal.

Hope this Helps!!!

7 0
3 years ago
3) -x + 5 = -11x + 25
konstantin123 [22]

Answer:

x=2

Step-by-step explanation:

-x+5=-11x+25

add +x on both sides -11x+x =-10x

-10x+25=5

subtract 25 on both sides

you get -10x=-20

x=2

6 0
3 years ago
30 men repair a road in 56 days by working 6 hours daily. In how many days 45 men will repair the same road by working 7 hours?
Softa [21]

time taken is 32 days,!!!!

4 0
3 years ago
Read 2 more answers
What is the distance between -8/5 and -3/5<br> A.-1<br> B.1<br> C.11/5<br> D. -11/5
Maurinko [17]

Answer:

1

Step-by-step explanation:

Subtract the two numbers and take the positive value  ( since distance is positive)

-8/5 - (-3/5)

-8/5 + 3/5

-5/5

-1

Taking the positive value, 1

4 0
2 years ago
The Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
kirza4 [7]

Answer:

Step-by-step explanation:

given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

Clerk          I           II           III    total

   

Pack      0.33          0.23    0.44 1

   

Defective 0.02 0.025    0.015  

   

Pack&def 0.0066 0.00575 0.0066 0.01895

a)  probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate

= P(II clerk) -P(II clerk and defective) = 0.23-0.00575=0.22425

b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)

=0.01895

c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3

=P(clerk 3 and def)/P(defective)

=\frac{0.0066}{0.01895} \\=0.348285

8 0
3 years ago
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