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3 years ago

What is 3.2 - 5.1n - 3n + 5 simplified

Mathematics

2 answers:

kkurt [141]3 years ago

5 0

Answer:

8.2-8.1n

Step-by-step explanation:

First of all, lets do the n part. WE have -5.1n-3n which equals -8.1n. Then, we have 3.2+5, which is 8.2. So we have 8.2-8n or -8.1n+8.2

nalin [4]3 years ago

3 0

Answer:

−8.1n+8.2

Step-by-step explanation:

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3. Write 13 tens as hundreds<br> and tens.

Alecsey [184]

Answer:

1 hundred and 3 tens

Step-by-step explanation:

I assume you mean 130 as hundreds and tens and the answer to that would be 1 hundred and 3 tens.

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2 years ago

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Stephanie is a taxi driver. She rents her taxi for $300/week. She feels she can take in $120/day in fares. Let D be the number o

Lesechka [4]

Answer: a. (0, -300), (1, -180), (2, -60), (7, 540)

b. T=120D-300

c. $28080

Step-by-step explanation:

a. T=120D-300 ==> per week

D=0: T=120(0)-300

D=0: T=-300 ==> (0, -300)

D=1: T=120(1)-300

D=1: T=120-300

D=1: T=-180 ==> (1, -180)

D=2: T=120(2)-300

D=2: T=240-300

D=2: T=-60 ==> (2, -60)

D=7: T=120(7)-300

D=7: T=840-300

D=7: T=540 ==> (7, 540)

b. T=120D-300

c. T=120(7)-300

T=840-300

T=$540 per week

1 year = 52 weeks

540*52=$28080

6 0

2 years ago

90 POINTS!!!!! Given: KLIJ inscr. in k(O),m∠K = 64°, measure of arc LI = 69°, measure of arc IJ = 59°, measure of arc KJ =97°

Kay [80]

In any cyclic quadrilateral, angles opposite one another are supplementary, meaning

$m\angle K+m\angle I=m\angle L+m\angle J=180^\circ$

and given that $\boxed{m\angle K=64^\circ}$ , we have $\boxed{m\angle I=116^\circ}$ .

By the inscribed angle theorem,

$m\angle JLK=\dfrac12m\widehat{KJ}$

$m\angle ILJ=\dfrac12m\widehat{IJ}$

and since

$m\angle L=m\angle JLK+m\angle ILJ$

we have

$m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}$

and it follows that

$m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}$

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3 years ago

Which relation is a function?

lina2011 [118]

Answer:

Step-by-step explanation:

For a relationship to be a function

Each value of x in the domain can only have 1 unique value of y in the range. That is, one-to-one correspondence.

The only relation which meets this criteria is B

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3 years ago

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3/5 ÷ 2 as a Fraction

docker41 [41]

Answer:

1/3 AMOSC T.rhecc

Step-by-step explanation:

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3 years ago

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