1/2 + 1/3= whats the answer

SIMILAR TRIANGLES<br> Solve for x.

patriot [66]

Answer:

Step-by-step explanation:

To do this, we need to do a few things. I'll put the steps separate so you can easily understand.

<h3>Step 1: Set up a proportion</h3>

$\frac{14}{6} = \frac{x}{4}$

<h3>Step 2: Cross multiply</h3>

6x = 14 x 4

6x = 56

6x = 9 1/3

<h3>Step 3: Check</h3>

$\frac{14}{6} = \frac{6}{9\frac{1}{3} }$

Cross multiply to check if they equal

6 x 9 1/3 = 14 x 4

56 = 56 ✔

<h3>Step 4: Answer</h3>

x = 9 1/3

I'm always happy to help :)

7 0

3 years ago

Evelyn went shopping with half of her monthly allowance. She spent $39.95 on a dress and 3/7 of the remainder on some accessorie

Gnoma [55]

Answer:

Evelyn monthly allowance is $187.

Step-by-step explanation:

Let the monthly allowance be 'x'.

Given:

Money taken with for shopping = $\frac{x}{2}$

Money spent of dress = $39.95

Also Given:

3/7 of the remainder on some accessories.

Money spent on accessories is equal to $\frac{3}{7}$ times Difference of monthly allowance and Money spent of dress.

framing in equation form we get;

Money spent on accessories = $\frac{3}{7}\times(\frac{x}{2}-39.95)$

Also Given:

Money left after shopping = $30.60

Now we know that;

Money taken with for shopping is equal to sum of Money spent of dress and Money spent on accessories and Money left after shopping.

framing in equation form we get;

$\frac{x}{2}=39.95+\frac{3}{7}(\frac{x}{2}-39.95)+30.60\\\\\frac{x}{2}=39.95+\frac{3x}{14}- 17.12 +30.60$

Combining like terms we get;

$\frac{x}{2}-\frac{3x}{14}=39.95-17.12+30.60\\\\\frac{x}{2}-\frac{3x}{14}= 53.43$

Now we will make denominator common using L.C.M

$\frac{x\times 7}{2\times7}-\frac{3x\times1}{14\times1}= 53.43\\\\\frac{7x}{14}-\frac{3x}{14}= 53.43\\\\\frac{7x-3x}{14}=53.43\\\\\frac{4x}{14}=53.43\\\\4x=53.43\times14\\\\x= \frac{53.43\times14}{4} = \$187$

Hence Evelyn monthly allowance is $187.

3 0

4 years ago

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago

Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.

Leto [7]

Hello,

Very nice like question!

a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)

P'(2)=0*2+3*1/2=3/2

b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3

Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)

Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12

7 0

3 years ago

⚠️Help ya boi with this question⚠️

jonny [76]

Answer:

ITS 21

Step-by-step explanation:

4 0

3 years ago