3 years ago

I WILL GIVE BRAINLIEST!!!

Mathematics

2 answers:

Korvikt [17]3 years ago

8 0

For what- there’s no pic sorry

Pavel [41]3 years ago

5 0

Answer:

The second one ig......

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3 years ago

Can somebody help I’ll give brainless plss

Anestetic [448]

Answer:

$93.22

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3 years ago

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$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right) \ \textgreater \ \ln \left(6^x\right)=\ln \left(21\right)$

$\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \ \ln \left(6^x\right)=x\ln \left(6\right)$

$x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \ \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)}$

$Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}$

In your case ln means $\frac{log 21}{log 6}$

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