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3 years ago

Can you please solve it A) 7/15 B) 1 C) 11/12 D) 11/4

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

The answer is 13/12 or 1.083 or 1 1/12 not any of those choices

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Answer:

8x8= 64 divided by 2 = 37

Step-by-step explanation:

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3 years ago

There are 7 bags. 2 bags are big. The rest are small.How many bags are small?

siniylev [52]

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3 years ago

The seating capacity of a theater is 250. Tickets are $3 for children and $5 for adults. The theater must take in at least $1100

maksim [4K]

Answer:

x + y ≤

3x + 5y ≥ 1100

Step-by-step explanation:

Given:

Seating capacity of theater = 250

Cost of each child ticket = $3

Cost of each adult ticket = $5

Cost per performance = $1100 at least

Find:

System of inequalities

Computation:

Let;

x = Number of children's tickets

y = Number of adult tickets

x + y ≤

3x + 5y ≥ 1100

5 0

2 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago