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gregori [183]
3 years ago
14

What is less 2/10 or 10/6?

Mathematics
1 answer:
Ann [662]3 years ago
4 0
This is obvious, 2/10 is less than one
10/6 is more than 1 so
2/10<1<10/6
therfor 2/10 is less

the legit way to do it is
convert bottom numbers to same number
number is 30

2/10 times 3/3=6/10
10/6 times 5/5=50/30

6/10<50/30
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Your answer to this question is definitely C!
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3 years ago
3) Scenario 1 Scenario 2 y = 50x x is time in hours y is distance in miles Compare the scenarios and determine which shows the g
Olegator [25]

Answer:

Option A.

Step-by-step explanation:

Consider the below figure attached with this question.

Scenario 1 represented by the graph.

From the graph it is clear that the line passes through the points (1,60) and (2,120).

Slope of the line is

y=\dfrac{y_2-y_1}{x_2-x_1}

y=\dfrac{120-60}{2-1}=60

The slope of line is 60. It means the speed is 60 miles per hour.

Scenario 2 defined by the equation,

y=50x

If an equation defined as y=mx+b, then m is slope and b is y-intercept.

m=50

The slope of line is 50. It means the speed is 50 miles per hour.  

The slope of Scenario 1 is greater than slope of Scenario 2. So, the Scenario 1 shows the greater speed.

Hence, the correct option is A.

6 0
3 years ago
Read 2 more answers
Find an expression for the area enclosed by quadrilateral ABCD below.
Helga [31]
  • ∆ABD is right angled hence area:-

\\ \sf\longmapsto \dfrac{1}{2}bh

\\ \sf\longmapsto \dfrac{1}{2}(4x)(3x)

\\ \sf\longmapsto \dfrac{1}{2}(12x^2)

\\ \sf\longmapsto 6x^2

There is only one option containing 6x^2 i.e Option D.

Hence without calculating further

Option D is correct

6 0
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MrRissso [65]

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6 0
2 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

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Read more about quadratic equations at

brainly.com/question/1214333

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