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makvit [3.9K]
2 years ago
14

If you leave a cup of hot chocolate sitting on a table what eventually happens to the temperature? Does the temperature ever rea

ch a thermal equilibrium?
Chemistry
1 answer:
Ksivusya [100]2 years ago
8 0

Ah , a cup of hot chocolate is alot of chocolate. Im gonna drool ; )

Well , heat flows from an area of high temperature to an area of low temperature. Here , hot chocolate has the high temp , and the surrounding has a room temp. So , the heat from the hot chocolate will dissipate into the surroundings and create a thermal equilibrium. So youre right.

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How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant
nika2105 [10]
<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 0.025305 \ mol \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0
2 years ago
The average rate of disappearance of ozone in the reaction 2o3(g) → 3o2(g) is found to be 7.25×10–3 atm over a certain interval
worty [1.4K]
<h3><u>Answer</u>;</h3>

1.0875 x 10-2 atm

<h3><u>Explanation;</u></h3>

2O3(g) → 3O2(g)

rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t  

The average rate of disappearance of ozone ... is found to  

be 7.25 × 10–3 atm over a certain interval of time.

This means (ignoring time)

∆[O3]/∆t = -7.25 × 10^–3 atm  

(it is disappearing, thus the negative sign)

rate = -(1/2)∆[O3]/∆t  

rate = -(1/2)*(-7.25 × 10^–3 atm)

      = 3.625 × 10^–3 atm  

Now use the other part of the expression:  

rate = +(1/3)∆[O2)∆t  

3.625 × 10–3 atm = +(1/3)∆[O2)/t  

∆[O2)/∆t = (3)*(3.625× 10^–3 atm)

              = 1.0875 x 10-2 atm over the same time interval

4 0
3 years ago
The acetic acid/acetate buffer system is a common buffer used in the laboratory. Write the equilibrium equation for the acetic a
hichkok12 [17]

Answer:

CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base or vice versa.

For the acetic acid buffer, CH₃CO₂H is the weak acid and its conjugate base is the ion without H⁺, that is CH₃CO₂⁻. The equilibrium equation in water knowing this is:

<h3>CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺</h3>

<em>In the equilibrium, the acid is dissociated in the conjugate base and the hydronium ion.</em>

8 0
3 years ago
List the following bond types in order of increasing strength: non-polar covalent bonds, ionic bonds, hydrogen bonds, polar cova
ss7ja [257]

Answer: Option (B) is the correct answer.

Explanation:

  • An ionic bond is formed by the sharing of electrons between two chemically combining atoms.

In an ionic bond, there occurs attraction between oppositely charged ions due to which there occurs strong forces of attraction between them. Therefore, ionic bonds are the strongest bonds.

  • A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, H_{2}O is a polar covalent compound. Partial opposite charges tend to develop on the atoms of a polar covalent compound.

  • A non-polar covalent bond is formed due to equal sharing of electrons between the combining atoms.

For example, Cl_{2} is a non-polar covalent molecule. No partial charges will be there on the atoms of a non-polar covalent molecule.

  • A hydrogen bond is defined as the bond formed between a hydrogen atom and an electronegative atom.

For example, in HCl compound there occurs hydrogen bonding.

In this type of bond, dipole-dipole attractive interactions tend to take place. And, strength of hydrogen bonds is very weak.

Thus, we can conclude that given bond types are arranged in order of increasing strength as follows.

      Hydrogen bonds < non-polar covalent bonds < polar covalent bonds < ionic bonds

8 0
3 years ago
The density of water at 40°c is 0.992 g/ml. what is the volume of 3.45 g of water at this temperature?
wariber [46]
3.45÷0.992=3.48ml
...
8 0
3 years ago
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