1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liq [111]
2 years ago
9

How intermolecular forces are broken during evaporation?

Chemistry
2 answers:
Tanzania [10]2 years ago
5 0

Answer: If the intermolecular forces are weak, then molecules can break out of the solid or liquid more easily into the gas phase. Consider two different liquids, one polar one not, contained in two separate boxes. We would expect the molecules to more easily break away from the bulk for the non-polar case. If the molecules are held tightly together by strong intermolecular forces, few of the molecules will have enough kinetic energy to separate from each other. They will stay in the liquid phase, and the rate of evaporation will be low. ... They will escape from the liquid phase, and the rate of evaporation will be high. To make water evaporate, energy has to be added. The water molecules in the water absorb that energy individually. Due to this absorption of energy the hydrogen bonds connecting water molecules to one another will break.

Hope this helps..... Stay safe and have a Merry Christmas!!!!!!!! :D

Sladkaya [172]2 years ago
3 0
If the molecules are held tightly together by strong intermolecular forces, few of the molecules will have enough kinetic energy to separate from each other. They will stay in the liquid phase, and the rate of evaporation will be low. ... They will escape from the liquid phase, and the rate of evaporation will be high
You might be interested in
How many neutrons are in Cesium-130 (130/50 Cs)
Sergeeva-Olga [200]
 Best Answer:<span>  </span><span>Cross sections for formation of cesium and rubidium isotopes produced by bombardment of uranium with protons ranging in energy from 0.1 to 6.2 Bev were measured both radiochemically and mass spectrometrically. Independent yields were determined for Rb/sup 84/, Rb/sup 86/, Cs/sup 127/, Sc, su p 129/. Cs/sup 130/, Cs/sup 131/, Cs/sup 132/, Cs/sup 134/, Cs/sup 136/, and, at some e nergies, Rb/sup 83 and Cs/sup 135/. In addition, the independent yield of Ba/sup 131/ and the chain yields of Cs/sup 125/, Cs/sup 127/, Cs/sup 129/, La/sup 131/, Cs/sup 135/, Cs/sup 137/, ion cross sections of the Cs and Ba products on the neutron- excess side of stability decrease monotonically with increasing energy above 0.1 Bev, whereas the excitation functions for independent formation of the more neutron-deficient products in the Cs-Ba region and of Rb/sup 84/ and Rb/sup 86/ all go through maxima. The proton energies at which these maxima occur fall on a smooth curve when plotted against the neutronproton ratio of the product, with the peaks moving to higher energies with decreasing neutron-proton ratio. Under the assumption that the mass-yield curve in the region 125 < A < 140 is rather flat at each proton energy, the crosssection data in the Cs region can be used to deduce the charge dispersion in this mass range. Plots of log sigma vs N/Z (or Z--Z/sub A/) show symmetrical bell-shaped peaks up to a bombarding energy of 0.38 Bev, with full width at halfmaximum increasing from 3.3 Z units at 0.10 Bev to about 5 Z units at 0.38 Bev, and with the peak position (Z/sub p/) moving from Z/ sub A/ -- 1.44 to Z/sub A/ -- 0.85 over the same energy range. At all higher energies, a double-peaked charge distribution was found, with a neutron-excess peak centered at N/Z approximates 1,515(Z/sub p/ approximates Z/sub A/ -- 1.9), and having approximately constant width and height at bombarding energies greater than 1 Bev. The peak on the neutron-deficient side which first becomes noticeable at 0.68 Bev appears to become broader and shift slightiy to smaller N/ Z values with increasing energy, The two peaks are of comparable height in the Bev region, and the peak-to-valley ratio is only approximates 2. The total formation cross section per mass number in the Cs region decreases from approximates 52 mb at 0.1 Bev to about 29 mb at 1 Bev and then stays approximately constant; the contribution of the neutron-excess peak above 1 Bev is about 12 mb. The neutron-excess peak corresponds in width and position to that obtained in fission by approximates 50-Mev protons. The recoil behavior of Ba/sup 140/ lends support to the idea that the neutron-excess products are formed in a lowdeposition-energy process. The recoil behavior of Ba/sup 131/ indicates that it is formed in a high-deposition-energy process. Post-fission neutron evaporation is required for the observed characteristics of the excitation functions of the rubidium isotopes and the neutron-deficient species in the Cs region. The correlation between neutron-proton ratios and positions of excitation function maxima is semiquantitatively accounted for if fission with unchanged charge distribution, followed by nucleon evaporation, is assumed. (auth) 
</span>
4 0
3 years ago
An organic compound (A) reacts with HCN to give (B). On hydrolysis of (B) in acidic medium gives (C). Compound (A) also produces
Vinil7 [7]

Answer:

Hydrolic Acid

Explanation:

7 0
3 years ago
How many kilojoules of heat are produced when 34.0 g of Fe2O3 reacts with an excess of
kupik [55]

Answer: this is your answer 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3

Explanation:

hope this helps ;) - Mal

4 0
3 years ago
Which of these are chemical changes in matter? Check all that apply.
LenKa [72]
I can not answer the question without the answer choices, when it is put up i will be able to answer the question. 
6 0
3 years ago
Read 2 more answers
In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses.
tia_tia [17]

the two process that occur in a cell are

oxidation: this is loss of electron by electrode. the metal electrode loaes electrons and get oxidized and forms ions

the ions get migrated to solution


Reduction: here the ions present in solution gains electron and get deposited on electrodes.

so gain of electrons is by ions


electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.



5 0
3 years ago
Read 2 more answers
Other questions:
  • An animal cell contains a nucleus and other organelles suspended in a watery solution that is encased in a flexible cell membran
    13·2 answers
  • Which of the following is a chemical property of the noble gases?
    7·2 answers
  • Unlike other types of lipids, phospholipids contain
    9·2 answers
  • Please help me. My chemistry teacher is not teaching us doing this epidemic
    13·1 answer
  • total kinetic energy of all the atoms that make up a sample of matter, would that be heat or mechanical????
    15·2 answers
  • Heat can be transferred from one material to another by direct touch, by differences in density in a fluid, and by ______ conduc
    6·1 answer
  • What can the bromine be classified as
    10·1 answer
  • Who organized the periodic table?
    12·2 answers
  • Which one of the following combinations cannot function as a buffer solution?
    8·1 answer
  • At the midpoint of a titration curve ________. At the midpoint of a titration curve ________. The concentration of a conjugate b
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!