Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute 
, therefore the probability that a container will be shipped is
It would be 73° and 17° because when you add them up it equals 90
42,42,24,36,60,6
1st Find the mean X̅
=(42+42+24+36+60+6)/6 = 35
2nd find the difference between the data set value and the mean (x - X̅)
and square them:
(42-35)² = 49
(42-35)² = 49
(24-35)² = 121
(36-35)² = 1
(60-35)² = 625
(6-35)² = 814
Now add up te result ∑(x-X̅)² =1659
Answer:
x=1/3,y=3
Step-by-step explanation:
y=7x+6_____equation1
5x+y=2_____equation2
substitute y into equation 2
5x+7x+6=2
12x+6=2
12x=2-6
12x=-4
x= -1/3
substitute X into equation 1
y=7x+6
y=7(-1/3)+6
y=-7/3+6
y=9/3
y=3
Answer:
what are the ordered pairs? then graph them and do the y axis number over the x axis number
Step-by-step explanation:
