3 years ago

42,42,24,36,60,6 Find the sum of the differences squared between the data entries and the mean.

1 answer:

3 0

42,42,24,36,60,6

1st Find the mean X̅ =(42+42+24+36+60+6)/6 = 35

2nd find the difference between the data set value and the mean (x - X̅)
and square them:
(42-35)² = 49
(42-35)² = 49
(24-35)² = 121
(36-35)² = 1
(60-35)² = 625
(6-35)² = 814
Now add up te result ∑(x-X̅)² =1659

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a father's age is three less than two times the son's age. the difference in their ages is 30 years. find the son's age.

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