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3 years ago

12

Which one of the following expressions is represented by the diagram?

2 answers:

marusya05 [52]3 years ago

8 0

Answer: D

Step-by-step explanation: It fills the requirements

Anvisha [2.4K]3 years ago

3 0

Answer:

Option D, 7 + (-6) -3

Hope this helps!

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A jeweler is dividing 3/8 of a pound of rubies amount 4 lots. What part of a pound will each lot weight?

ch4aika [34]

They will each equal 1.5 pounds also known as 1 1/2 or 3/2.

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3 years ago

PLEASE HELP! WILL MARK BRAINLIEST!! :D

netineya [11]

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Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.

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3 years ago

Is 5:20 and 15:60 equivalent

kati45 [8]

Answer:

Yes! When simplifying 15:60 by dividing each side by 3, you get 5:20, which is the same as 5:20.

Step-by-step explanation:

Hope this helps <3

5 0

3 years ago

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

3 years ago

Find the sum of the first six terms of the sequence for which a2=0.7 and a3=0.49.

alina1380 [7]

A1 = 0.91
a6 = -0.14
sum = (0.91+-0.14) /2
sum = 2.31

8 0

3 years ago

Read 2 more answers