Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
There are 45 girls in Jonathan's class.
12 - 2x = -2(y - x)
12 - 2x = -2y - (-2x)
12 - 2x = -2y + 2x
12 - 2x - 2x = -2y + 2x - 2x
12 - 4x = -2y
12 - 12 - 4x = -2y - 12
-4x = -2y - 12
-4x/4 = -2y/4 - 12/4
-x = -0.5y - 3
-x/-1 = -0.5y/-1 - 3/-1
x = 0.5y + 3
or
x = 3 + 0.5y
Answer:
the answer ia true
Step-by-step explanation:
hope this helps
87.5 percent
Reason: 40/40-5/40 is 35/40. Divide 35/40 and you get 0.875. Multiply by a hundred and you get 87.5%
