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ryzh [129]
3 years ago
14

How many total possible outcomes are there in the sample when you are flipping 3 coins: a penny, a nickel, and a dime?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0
8 because when you flip one coin there is 2 outcomes: heads and tails. Therefore if you flip 3 of them it is 2*2*2=8
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A digital camera memory card is 1/4 full. The card is 2/3 full when 375 more pictures have been taken.
marusya05 [52]
To get the answer first we have to find full numbers.
We can use proportion
2/3 ----------------------- 375
1 -------------------------- x
Crossmultiply now
2/3*x=375           /:2/3 
x=375: \frac{2}{3} 
x=375* \frac{3}{2}=562 - its the answer A)
Now we have to find how much were originally on the card.
To get the answer we can just multiply 562 times 1/4.
562*1/4=140 - its the asnwer B)
5 0
4 years ago
Read 2 more answers
Write an equation in slope intercept form that contains the points (-2,4) and (-1,6)
lina2011 [118]
The answer would be y=1/2x
7 0
3 years ago
Please help!!! I would like an explanation along with your answer. Thanks
Korvikt [17]

Answer:

x = 12/13

BC = 140/13

Step-by-step explanation:

If A is the mipoint of BC, then AB is half of BC.

AB = BC / 2

8x − 2 = (3x + 8) / 2

16x − 4 = 3x + 8

13x = 12

x = 12/13

BC = 3x + 8

BC = 3 (12/13) + 8

BC = 36/13 + 104/13

BC = 140/13

4 0
4 years ago
How do I solve this, pretty urgent please. ​
Andreas93 [3]

Answer:

  • 1

Step-by-step explanation:

<u>Substitute:</u>

  • x^{0.5} = y

<u>Then the expression becomes:</u>

  • (\dfrac{1+y^3}{1-y+y^2}-y) \dfrac{1-y^2}{1-y}  -y=\\
  • (\dfrac{(1+y)(1-y+y^2)}{1-y+y^2}-y) \dfrac{(1-y)(1+y)}{1-y}  -y=
  • (1+y-y)(1+y)-y=
  • 1(1+y)-y=
  • 1+y-y=
  • 1

The result is 1 regardless the value of x other than 1.

5 0
3 years ago
Which operations are commutative and associative?
Vadim26 [7]

Answer:

Step-by-step explanation:

if there are two numbers a and b.then

1. a+b=b+a ,commutative under addition.

2. ab=ba,commutative under multiplication.

If there are three numbers a,b,c then

1. a+(b+c)=(a+b)+c,associative under addition.

2.

a×(b×c)=(a×b)×c ,associative under multiplication.

6 0
3 years ago
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