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3 years ago

Simplify the following expression. 7^-5/6.7^-7/6. 1/491/141449

1 answer:

4 0

${7}^{ - \frac{5}{6} } \times {7}^{ - \frac{7}{6} } \\ = {7}^{ - \frac{5}{6} - \frac{7}{6} } \\ = {7}^{ - \frac{12}{6} } \\ = {7}^{ - 2} \\ = \frac{1}{ {7}^{2} } \\ = \frac{1}{49}$
The answer is 1/49

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At the first meeting of the Tennis Club, the 7 members decided to have a tournament in which every player will play a match agai

mariarad [96]

Answer:

21 matches

Step-by-step explanation:

This is a combination problem where we have to select two member out of 7 members

So we want calculation of 7C2

7C2 = 7!/[(2!)(7-2)!]

(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]

(7*6)/2 ~ Note everything that easily cancels here!

42/2

21 matches

5 0

2 years ago

Plz help me solve it the question is below

AlladinOne [14]

Answer:

$\frac{1024}{2025}$

Step-by-step explanation:

$\frac{3}{4}^{-4} = \frac{1}{\frac{3}{4}^{4} }$

(3/4)^4 = 81/256

1 ÷ 81/256 = 256/81

So;

$\frac{256}{81} * \frac{4}{9} = \frac{1024}{729}$

$\frac{1024}{729} / n = \frac{1}{9/25}$

$\frac{1024}{729n} = \frac{25}{9} \\\\n = \frac{1024 *9 }{25 * 729} = \frac{1024}{2025}$

6 0

3 years ago

Find the missing dimension use the scale factor 1:12 model 32 cm find the actual in m

gizmo_the_mogwai [7]

Given:

The scale factor is 1:12.

Dimension of model = 32 cm

To find:

The actual dimension in m.

Solution:

Let x be the actual dimension.

The scale factor is 1:12 and the dimension of model is 32 cm.

$\dfrac{1}{12}=\dfrac{32}{x}$

On cross multiplication, we get

$x=32\times 12$

$x=384\ cm$

$x=3.84\ m$ $[\because 1\ m=100\ cm]$

Therefore, the actual dimension is 3.84 m.

6 0

2 years ago

Probability of a standard six side dice landing on a four in the first three rolls?

Illusion [34]

Answer:

91/216

Step-by-step explanation:

The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.

P(at least one 4) = 1 − P(no 4s)

P(at least one 4) = 1 − (5/6)³

P(at least one 4) = 91/216

Alternatively, you can calculate it this way.

The probability of getting a 4 on the first roll is 1/6.

The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.

The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.

The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.

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2 years ago

wolverine [178]

The survey sample includes residents of the neighboring city whose phone number is listed.

4 0

3 years ago

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