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3 years ago

Simplify the following expression. 7^-5/6.7^-7/6. 1/491/141449

1 answer:

4 0

${7}^{ - \frac{5}{6} } \times {7}^{ - \frac{7}{6} } \\ = {7}^{ - \frac{5}{6} - \frac{7}{6} } \\ = {7}^{ - \frac{12}{6} } \\ = {7}^{ - 2} \\ = \frac{1}{ {7}^{2} } \\ = \frac{1}{49}$
The answer is 1/49

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Answer:

(x-3)^2 = 3

Step-by-step explanation:

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2 years ago

Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time he will use the Same amount of plan

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Answer:

3 7/12 kg

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

Step-by-step explanation:

On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.

Total plant bought = 4 1/2 kg

Strawberry = 1 2/3 kg

Tomato = 1/4 kg

Strawberry + tomato

= 1 2/3 + 1/4

= 5/3 + 1/4

= 20+3/12

= 23/12 kg

Total remaining after Sunday

= Total - used

= 4 1/2 - 23/12

= 9/2 - 23/12

= 54-23/12

= 31/12

= 2 7/12 kg

Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.

Strawberry = 2 × 1 2/3

= 2 × 5/3

= 10/3 kg

Tomato = 1 × 1/4

= 1/4 kg

Total plant needed to feed strawberry two more times and tomato 1 more time

= 10/3 kg + 1/4 kg

= 40+3/12

= 43/12 kg

= 3 7/12 kg

He will need 3 7/12 kg of plant

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

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3 years ago

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2 years ago

A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle

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Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

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3 years ago

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2 years ago