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Snowcat [4.5K]
2 years ago
8

I’m really struggling here :,D

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
6 0

Answer:

-2

Step-by-step explanation:

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Given 7x + 2 ≥ 58, which number is not in the solution set?
Natasha_Volkova [10]

Answer:

i can't see the rest of the question so i don't know the answer choices but:

since x≥8

whichever choice is less than 8 is incorrect

step-by-step explanation:

i can't see the rest of the question so i don't know the answer choices but:

7x≥56

x≥8

4 0
3 years ago
HELP PLZZ I WILL REWARD IF ANSWERS RIGHT
pentagon [3]
I know you have 1 and 3 right but I'm sorry about not knowing the rest.
8 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Need help asap 8 points
lubasha [3.4K]
Question 13 is 14 x is 14
7 0
3 years ago
Read 2 more answers
Alan found the value of the expression (15 - 6)2 to be 189. Is he right?
tatuchka [14]
Answer would be C

Because I always use the rule of :
B - Brackets
I - indices
D - division
M - multiplication
A - addition
S - subtraction
3 0
2 years ago
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