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3 years ago

2cot^2x-3csc=0 find all solutions of the equation in the interval [0,2pi)

Mathematics

2 answers:

jarptica [38.1K]3 years ago

8 0

Hope this helps you!

Genrish500 [490]3 years ago

3 0

Kind of lengthy but hope it helps! ;)

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Write the following in simplified radical form.

REY [17]

Step-by-step explanation:

I think the answer is like this

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3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

4 years ago

What is the 50th term in the sequence 17, 14, 11, 8, ...

Fed [463]

The answer would be -142, because you have to keep subtracting 3 and I got -142

8 0

3 years ago

What is the slope of the line that contains the points (0,7) and (8,-3)

Novay_Z [31]

Slope= $\frac{change in y}{change in x}$
slope m= $\frac{7--3}{0-8}$
m= $\frac{10}{-8}$

4 0

3 years ago

Read 2 more answers

The height of an object from a distance

olga55 [171]

Y = height
x = distance from tower

tan(19.9) = y/x

tan(21.8) = y/(x-50) ( x is 50 feet closer so subtract 50 from x)

find the tan of the angles:
tan19.9 = 0.362
tan21.8 = 0.400

replace those values in the equations:
0.362 = y /x
0.400 = y / (x-50)

rewrite to solve for height:
0.362x = y
0.400(x-50) = y distribute the 0.400 and rewrite as 0.400x-20 =y

now solve:

0.362x = 0.400x-20

add 20 to each side:
0.362x +20 = 0.400x

subtract 0.362x from each side:

20 = 0.038x

divide both sides by 0.038
x = 20 / 0.038 = 526.3 feet

now that x is known replace x in the original equation and solve for y:

tan19.9 = y /x

0.362 = y / 526.3
y = 0.362 x 526.3
y = 190.5

the height of the tower is 190.5 feet

7 0

3 years ago