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mestny [16]
3 years ago
5

2cot^2x-3csc=0 find all solutions of the equation in the interval [0,2pi)

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0
Hope this helps you!

Genrish500 [490]3 years ago
3 0
Kind of lengthy but hope it helps! ;)

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Please answer this for me
bogdanovich [222]

Answer:

B (5,2)

Step-by-step explanation:

6 0
3 years ago
Eh help me out<br> what 18% of 32
DIA [1.3K]

Answer:

5.76

Step-by-step explanation:

18% of 32

=18% x 32

=18/100 x 32

=576/100

=5.76

6 0
2 years ago
3. Planet Fitness Club charges $30 per month for a membership. 24-Hour Fitness Club charges $22 per month plus an $80 initial fe
umka2103 [35]

Answer:

The number of months after which amount paid to two fitness clubs be the same is 10

Step-by-step explanation:

Given as :

The charge of Mikes fitness center = $30 per month fro membership

The charge of All-Day fitness center= $22 per month fro membership + $80            

                                                              initiation charge

Let The number of months after which amount paid to each club be same = x

So, According to question :

30 x = 22 x + 80

Or, 30 x - 22 x = 80

Or, 8 x = 80

So     x =

∴       x = 10

Hence The number of months after which amount paid to two fitness clubs be the same is 10    Answer

7 0
3 years ago
Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)
timama [110]
<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\

Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

6 0
2 years ago
Explain how to subtract 247 from 538
Vladimir79 [104]
8-7=1 3-4=1 5-2=3  So it is 311.
4 0
3 years ago
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