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3 years ago

5

your employer has 600 business cards printed for you, and you give away 280 of them. To the nearest hundredth, what percent of t

he cards is left?

2 answers:

11111nata11111 [884]3 years ago

8 0

600 - 280 = 320 cards. The percent is then (320 / 600) x 100 = 53.33%.

arlik [135]3 years ago

4 0

The number of cards left is 600-280=320.

So the 320 cards left are what percent? we count it like this:
$\frac{320}{600}*100%= \frac{32}{60}*100%=\frac{32}{60}*100%$ =53.3..%

so the answer is 53.3%

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Please answer in only a fraction please..

fenix001 [56]

Answer:

19/40

Step-by-step explanation:

1.9*(1/4) =0.475

0.475=19/40

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2 years ago

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How does the brain get stronger when it takes on challenges?

Sergeu [11.5K]

<h2><em>Hello ! :)</em></h2>

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3 years ago

A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria

Kaylis [27]

Answer:

A) The expression for the number of bacteria is $P(t) = 400e^{0.7783t}$ .

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

$P' = kP$

where $P$ stands for the population of bacteria.

Writing $P'$ as $\frac{dP}{dt}$ , we get

$\frac{dP}{dt} = kP$ .

Notice that this is a separable equation, so

$\frac{dP}{P} = kdt$ .

Then, integrating in both sides of the equality:

$\int\frac{dP}{P} = \int kdt$ .

We have,

$\ln P = kt+C$ .

Now, taking exponential

$P(t) = Ce^{kt}$ .

The next step is to find the value for the constant $C$ . We do this using the initial condition $P(0)=400$ . Recall that this is the initial population of bacteria. So,

$400 = P(0) = Ce^{k0}=C$ .

Hence, the expression becomes

$P(t) = 400e^{kt}$ .

Now, we find the value for $k$ . We are going to use that $P(4)=9000$ . Notice that

$9000 = 400e^{k4}$ .

Then,

$\frac{90}{4} = e^{4k}$ .

Taking logarithm

$\ln\frac{90}{4} = 4k$ , so $\frac{1}{4}\ln\frac{90}{4} = k$ .

So, $k=0.7783788273$ , and approximating to the fourth decimal place we can take $k=0.7783$ . Hence,

$P(t) = 400e^{0.7783t}$ .

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

$P(5) =400e^{0.7783*5} = 19593.723 \approx 19593$ .

C) In this case we want to do the reverse operation: we want to find the value of t such that

$30000 = 400e^{0.7783t}$ .

This expression is equivalent to

$75 = e^{0.7783t}$ .

Now, taking logarithm we have

$\ln 75 = 0.7783t$ .

Finally,

$t = \frac{\ln 75}{0.7783} \approx 5.55$ .

So, after 5.55 hours the population of bacteria will reach 30000.

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3 years ago

Dion builds a pattern that is represented by the equation b equals 2 F + 6 where f is the figure number of the pattern and B is

Rzqust [24]

9514 1404 393

Answer:

24

Step-by-step explanation:

Using 9 as the figure number, Dion's equation tells us there are ...

2(9) +6 = 18 +6 = 24 blocks in figure 9

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3 years ago

If john run 2.5 miles everyday, how many miles will he run in a month of 30?

Lapatulllka [165]

Answer:

2,250 miles per day.

Step-by-step explanation:

John runs 2.5 miles per day. In a period of 30 months, you can averagely take 30 days in each month.

So, 30 x 30 = 900 days in 30 months.

To find the number of miles ran in 900 days,

900 x 2.5 = 2,250 miles per day.

Hope this helps.

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2 years ago