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3 years ago

GEOMETRY TRIANGLES I WILL GIVE BRAINLIEST H

Mathematics

1 answer:

nasty-shy [4]3 years ago

7 0

Answer: AC = 20

AC and BC are equal, so if you set -y + 23 as equal to 6y + 2, you get -y + 23 = 6y + 2. You can then subtract 2 from both sides, to get -y + 21 = 6y. Then add y to both sides, and you can get 7y = 21, which then simplifies to Y = 3. Then do -3 + 23 to find AC, to get 20.

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What is 2 3/2 equal to? A. 2√8 B. 3√8 C. 3√16 D. 2√16

aivan3 [116]

2 3/2 is not equal to any of these

5 0

3 years ago

What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

4 0

3 years ago

Solve systems of equations for y and x: −5y + 8x = −18 5y + 2x = 58

Natali5045456 [20]

Answer:

(4, 10)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

-5y + 8x = -18

5y + 2x = 58

Step 2: Solve for x

Elimination

Combine 2 equations: 10x = 40
[Division Property of Equality] Divide 10 on both sides: x = 4

Step 3: Solve for y

Substitute in x [Original equation]: -5y + 8(4) = -18
Multiply: -5y + 32 = -18
[Subtraction Property of Equality] Subtract 32 on both sides: -5y = -50
[Division Property of Equality] Divide -5 on both sides: y = 10

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3 years ago

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