m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
Answer:
275 units^2
Step-by-step explanation:
The formula for the area of trapezoid is:
Area=((b1+b2)/2)*h
In the given trapezoid, as it can be seen
b1=16
h=11
The lower base will be calculated using all the lengths in the lower base
b2=9+16+9
b=34
Putting the values in formula
Area=((16+34)/2)*11
Area=(50/2)*11
Area=25*11
=275 units^2
Answer:
12t^-6
Step-by-step explanation:
-4 + - 2 = - 6
2*6 = 12
Answer:
The measure of the two supplementary angles is
Small angle = x = 44°
Large angle = y = 136
Step-by-step explanation:
Supplementary angles are two angles whose measures add up to 180° .
Let
Small angle = x
Large angle = y
x + y = 180°.... Equation 1
The measure of the large angle is four more than three times the measure of the small angle
Hence: y = 4 + 3x
We substitute 4 + 3x for y in Equation 1
x + 4 + 3x = 180°
4x + 4 = 180°
4x = 180° - 4
4x = 176
x = 176/4
x = 44°
Solve for y
y = 4 + 3x
y = 4 + 3(44)
y = 4 + 132
y = 136°
Therefore, the measure of the two supplementary angles is
Small angle = x = 44°
Large angle = y = 136
Answer:
√12 in nearest tenth is 3.5 is the answer
