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Sergio039 [100]
2 years ago
8

What is x. pls help me​

Mathematics
2 answers:
Inessa05 [86]2 years ago
5 0
I believe it is 40 degrees because that is a right angle which is equivalent to 90 degrees. So 50 +40= 90. Hope this helps and have a nice day :)
ad-work [718]2 years ago
4 0

Answer:

x = 40

Step-by-step explanation:

plz mark my answer as brainlist plzzzz if you find it useful.

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Which table does NOT represent a linear function?
chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 8, 5, 2, -1

- we subtract 3 each time

\rule{200}{2}

Let's try the next one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 5, 10, 15, 20

- we add 5 each time

\rule{200}{2}

Let's try the third one:

  • x values: -1, 0, 1, 2
  • - we add 1 each time
  • y values: 15, 18, 20, 21

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0
2 years ago
Which property will Sarah use to solve 6x = 42?
grin007 [14]

Answer:

multiplication property of equality

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
Mamont248 [21]

Answer:

y=-5x+12


Step-by-step explanation:

just use a graphing calculator and basic knowledge of slope intercept form

7 0
2 years ago
Anyone know the answer to this algebra problem?
ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

<u>Step-by-step explanation:</u>

\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}

\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}

3 0
3 years ago
Help me please with this math question asap
steposvetlana [31]

Answer:

5

Step-by-step explanation:

A function

a \times  {b}^{x}

where a is the initial value and b is the multiplicative rate of change.

In the function,

f(x) = 2 \times  {5}^{x}

5 is the value of b so

5 is the multipicative rate of change

8 0
2 years ago
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