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zvonat [6]
2 years ago
15

Solving one-step equation

Mathematics
1 answer:
Vika [28.1K]2 years ago
4 0
96 is the answer or 69
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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
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3 years ago
27x 5 + 9x 4 - 18x 3) 9x 2
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In guessing it's 2,106.......
4 0
3 years ago
Solve |3k-2|=2|k+12|
Stella [2.4K]

Answer:

k = 26   or   k = -\dfrac{22}{5}

Step-by-step explanation:

|3k - 2| = 2|k + 12|

\dfrac{|3k - 2|}{|k + 12|} = 2

|\dfrac{3k - 2}{k + 12}| = 2

3k - 2 = 2(k + 12)   or   3k - 2 = -2(k + 12)

3k - 2 = 2k + 24   or   3k - 2 = -2k - 24

k = 26   or   5k = -22

k = 26   or   k = -\dfrac{22}{5}

7 0
3 years ago
F Tanisha has ​$ 1,000 to invest at 5 % per annum compounded ​, how long will it be before she has ​$1,400 ​? If the compounding
vladimir2022 [97]

With annual compounding, the number of years for 1000 to become 1400 is 6.7 years

With continous compounding, the number of years for 1000 to become 1400 is 1.35 years

<h3>How long would it take $1000 to become $1,400?</h3>

With annual compounding, the formula that would be used is:

(In FV / PV) / r

Where:

  • FV = future value
  • PV = present value
  • r = interest rate

(In 1400 / 1000) / 0.05 = 6.7 years

With continous compounding, the formula that would be used is:

(In 1400 / 1000) / (In e^r)

Where r = interest rate

((In 1400 / 1000) / (In e^0.05) = 1.35 years

To learn more about how to determine the number of years, please check: : brainly.com/question/21841217

#SPJ1

5 0
2 years ago
A quadrilateral has two angles that measure 120° and 140°. The other two angles are in a ratio of 2:3. What are the measures of
Furkat [3]
40 degrees and 60 degrees
8 0
3 years ago
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