2 years ago

What is 999 - 1 -1 1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 +1 + 11 -1 = ???

Mathematics

2 answers:

atroni [7]2 years ago

8 0

988:)))))))))))))) i hope its true

Ulleksa [173]2 years ago

4 0

Answer: Hello!

your answer is

<h2>990</h2><h3>pls brainliest :)</h3>

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Given that aₙ = (-2) (5)ⁿ⁻1 for a geometric sequence, determine the common ratio:

patriot [66]

Answer:

Step-by-step explanation:

The nth term of the geometric sequence is

$a_n=(-2)(5)^{n-1}$

In general the nth term of a geometric sequence is

$a_n=a_1(r)^{n-1}$

By comparism;

$r=5$ is the common ratio of the sequence.

$a_1=(-2)(5)^{1-1}=-2$

$a_2=(-2)(5)^{2-1}=-10$

Common ratio is

$r=\frac{-10}{-2}=5$

4 0

3 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .