Answer:
5
Step-by-step explanation:
The nth term of the geometric sequence is

In general the nth term of a geometric sequence is

By comparism;
is the common ratio of the sequence.
Or


Common ratio is

The cross product of two vectors gives a third vector

that is orthogonal to the first two.

Normalize this vector by dividing it by its norm:

To get another vector orthogonal to the first two, you can just change the sign and use

.